PLEASE HELP
NASA scientists have determined that the chance a single person would get hit by a piece of falling satellite is one in 3,200. What can you infer based on this probability?
A. Satellites that enter Earth’s atmosphere land mostly in the ocean.
B. NASA does a good job informing people of when satellites will enter the atmosphere.
C. Satellites that enter Earth’s atmosphere land mostly in unpopulated areas.
D. Much of a satellite is destroyed during the process of entering Earth’s atmosphere.
Answer:
a) 18.75 ft^2
b) 2.5 ft
c) 12.07 ft
d) 10 ft
e) 1.553 ft
f) 1.875 ft
Explanation:
Given data :
5.0-ft bed width, ( b )
2.5-ft depth ( y )
1 : 1 side slope
Evaluate
a) Area of trapezoidal section
A = by + my^2
we assume m = 1
A = [5 + (1 * 2.5 ) ] *2.5
= ( 7.5 ) 2.5 = 18.75 ft^2
b) Calculate water depth
water depth = 2.5 ft
c) Calculate wetted perimeter
P = b + 2y √ 1 + m^2
= 5 + (2.5*2) √ 1 + 1 ^2 = 12.07 ft
d) calculate top width
T = b + 2my
= 5 + 2 ( 1 * 2.5 ) = 10 ft
e) calculate hydraulic radius
R = A / P = 18.75 / 12.07
= 1.553 ft
f) calculate hydraulic depth
D = A / T = 18.75 / 10 = 1.875 ft
Friday and Saturday night
Answer:29,930 kJ
Explanation:
Given
Car starts with an initial elevation of 500 m and drives up a hill to reach a final elevation of 2000 m
Final velocity (V)=20 m/s
Energy of car increases by 100 kJ
mass of car(m)=2000 kg
Total Energy=29,430+400+100=29,930 kJ
Answer:
Q convection = 11.361 W
Q radiation = 21.438 W
Explanation:
Given data:
Pr = 0.7
Isobaric volume expansion is calculated as
L = 0.5 m Since door is vertical
grasshoff number is
Gr = 1.79\times 10^8
Rayleigh number
Ra = GrPr
therefore given flow is laminar
Nusselt number is
Nu = 62.4223
Heat transfer coefficient
h = 3.246 W/m^2 K
convection heat transfer
Q = 11.361 W
Radiation heat transfer
