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Kobotan [32]
3 years ago
10

A person wearing rollerblades starts from rest and accelerates at a constant rate. She reaches a speed of 13 mph (5.18 m/s) exac

tly 18.0 s later.
a. What is the magnitude of their average acceleration (in m/s2)?
b. How far does the person on rollerblades travel in that period of time?

Physics
2 answers:
Vinil7 [7]3 years ago
8 0
Answer:
a. Acceleration = 0.28 m/s^2
b. Distance = 45.36 m

Explanation:

kvv77 [185]3 years ago
5 0

Answer: a. ) What is the magnitude of their average acceleration (in m/s2)

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How is the q of an rlc parallel resonant circuit calculated?
notka56 [123]

Answer:

It is calculated by dividing Resistance, R, by Inductive reactance, XL.

Explanation:

Q is called the Q factor of a resonance circuit. In a parallel resonance circuit, it is calculated by finding the ratio of the power stored in the circuit to the power distributed in the circuit. It is a way of measuring the quality of a circuit or how effective the circuit is.

Q factor is the inverse in the resonance series circuit.

Q factor of a resonance parallel circuit,

<h3>Q = R/XL</h3>

R = Resistance

XL = Inductive reactance

3 0
3 years ago
Can someone please help, ;w;?
SOVA2 [1]
I believe the answer is 3). The cell wall provides protection, it doesn’t control movements of materials in and out of the cell.
7 0
4 years ago
Read 2 more answers
PLEASE HELP AS FAT WILL GIVE BRAILIEST TO MOST SPECIFIC AND CORRECT ANSWER
Bas_tet [7]

Answer:

Time

Explanation:

8 0
4 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed
kogti [31]

Answer:

a)y_{first}=5.3mm

b)y_{second}=10.6-5.3 =5.3 mm  

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

y=\frac{m\lambda D}{a} when m is a natural number.

here:

  • m is 1 (to find the central bright fringe)                
  • D is the distance from the slit to the screen
  • a is the slit wide
  • λ is the wavelength

So we have:

y_{first}=\frac{633*10^{9}*3.35}{0.0004}

y_{first}=5.3mm

b)

Now, if we do m=2 we can find the distance to the second minima.

y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}

y_{2}=10.6 mm

Now we need to subtract these distance, to get the width of the first bright fringe :

y_{second}=10.6-5.3 =5.3 mm    

I hope it heps you!

     

4 0
3 years ago
Write the electron configurations for titanium (Ti), vanadium (V), chromium (Cr), and manganese (Mn).
Tomtit [17]
See from periodic table the proton or atomic number of elements u want to know about then as u know first electron shell can hold 2 electrons 2nd can hold eight as well as all others........protons are equal to electrons so divide proton number into shells but remember to use amounts which it can hold

CHEERS !!
8 0
3 years ago
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