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Kobotan [32]
3 years ago
10

A person wearing rollerblades starts from rest and accelerates at a constant rate. She reaches a speed of 13 mph (5.18 m/s) exac

tly 18.0 s later.
a. What is the magnitude of their average acceleration (in m/s2)?
b. How far does the person on rollerblades travel in that period of time?

Physics
2 answers:
Vinil7 [7]3 years ago
8 0
Answer:
a. Acceleration = 0.28 m/s^2
b. Distance = 45.36 m

Explanation:

kvv77 [185]3 years ago
5 0

Answer: a. ) What is the magnitude of their average acceleration (in m/s2)

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2 years ago
A chair exerts a force of 20 N on a floor and is not moving. What force does
AysviL [449]

The floor exerts 20 N of force on the chair

Explanation:

We can answer this question by using Newton's third law, which states that:

<em>"When an object A exerts a force (called action) on an object B, object B exerts an equal and opposite force (called reaction) on object A"</em>

In this problem, we can identify:

- Object A as the chair

- Object B as the floor

This means that the force of 20 N exerted by the chair on the floor is the action, and so the force exerted by the floor on the chair is the reaction. Newton's third law states that these two forces are equal and opposite: therefore, the force exerted by the floor on the chair is also 20 N, but in the opposite direction.

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3 years ago
According to the Can Manufacturers Institute, the energy used to make an aluminum can from recycled aluminum is 5% of the energy
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Answer:

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3 years ago
A rock climber stands on top of a 50 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s a
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<h2><em>Answer: b) What was the initial speed of the second stone?</em></h2>

Explanation:

3 0
3 years ago
An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g
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The astronaut will take 300 seconds

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum of the astronaut+object system must be conserved.

Initially, they are both at rest, so their total momentum is zero:

p=0

After the astronaut throws the object, their total momentum is:

p=MV+mv

where:

M = 80 kg is the mass of the astronaut

V is the final velocity of the astronaut

m = 500 g = 0.5 kg is the mass of the object

v = 8.0 m/s is the velocity of the object

Since momentum is conserved, we can write

0=MV+mv

And solving for V,

V=-\frac{mv}{M}=-\frac{(0.5)(8.0)}{80}=-0.05 m/s

Which means that he starts moving at 0.05 m/s in the direction opposite to the object.

Now the astronaut needs to cover a distance of

d = 15.0 m

And his speed is

v = 0.05 m/s

Therefore, the time taken is

t=\frac{d}{v}=\frac{15.0}{0.05}=300 s

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4 years ago
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