An older-model car accelerates from 0 to speed v in 9.0 s. A newer, more powerful sports car of the same mass accelerates from 0
1 answer:
You might be interested in
b) the net force on the car is zero.
Explanation:
Let's analyze each option one by one:
a) the force from the engine is greater than all the forces of friction. --> FALSE. In fact, the car is moving at constant velocity: this means that its acceleration is zero,
a = 0
and so Newton's second law becomes
where is the net force on the car and m is its mass. This means that the net force on the car is zero: so, the force from the engine cannot be greater than all the forces of friction, otherwise the net force cannot be zero.
b) the net force on the car is zero. --> TRUE, for what we said at point A)
c) the inertia is changing. --> FALSE. The inertia of an object just depend on the mass and the velocity of the object: as neither the mass nor the velocity are changing in this problem, then the inertia of the car is not changing.
d) the forces of friction are proportional to the acceleration of the car. --> FALSE. Generally, the force of friction acting on an object moving on a flat surface is
where is the coefficient of friction, m is the mass, and g the acceleration of gravity. Therefore, the force of friction does not depend on the acceleration of the car.
e) All of the above. --> FALSE
Learn more about net force and Newton's second law:
#LearnwithBrainly
Answer:
<h2>73 kg</h2>Explanation:
The mass of the object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>73 kg</h3>Hope this helps you
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
a E =
b E =
c E = 0 N/C
d
e
f V =
g
h
i
Explanation:
From the question we are given that
The first charge
The second charge
The first radius
The second radius
And
The objective is to obtain the the magnitude of electric for different cases
And the potential difference for other cases
Considering a
r = 4.00 m
Considering b
This implies that the electric field would be
This because it the electric filed of the charge which is below it in distance that it would feel
=
Considering c
r = 0.200 m
=>
The electric field = 0
This is because the both charge are above it in terms of distance so it wont feel the effect of their electric field
Considering d
r = 4.00 m
=>
Now the potential difference is
This so because the distance between the charge we are considering is further than the two charges given
Considering e
r = 1.00 m
Considering f
Considering g
Considering h
Considering i
