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3 years ago

Give the atomic mass and atomic number of this atom.

Physics

1 answer:

Soloha48 [4]3 years ago

4 0

I think it would be sodium.

Because the atomic mass is protons + neutrons, so I did 6 + 5 = 11
Then I looked on the periodic table for an element with the atomic mass of 11 and it was Na... Sodium.

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C. Gamma rays have more energy than infrared rays

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3 years ago

Tether ball is a game children play in which a ball hangs from a rope attached to the top of a tall pole. The children hit the b

Murljashka [212]

Answer:

a_total = 14.022 m/s²

Explanation:

The total acceleration of a uniform circular motion is given by the following formula:

$a=\sqrt{a_c^2+a_T^2}$ (1)

ac: centripetal acceleration

aT: tangential acceleration

Then, you first calculate the centripetal acceleration by using the following formula:

$a_c=r\omega^2$

r: radius of the circular trajectory = 2.0m

w: final angular velocity of the ball = 7.0 rad/s

$a_c=(2.0m)(7.0rad/s)^2=14.0\frac{m}{s^2}$

Next, you calculate the tangential acceleration. aT is calculate by using:

$a_T=r\alpha$ (2)

α: angular acceleration

The angular acceleration is:

$\alpha=\frac{\omega_o-\omega}{t}$

wo: initial angular velocity = 13 rad/s

t: time = 15 s

Then, you use the expression for the angular acceleration in the equation (1) and solve for aT:

$a_T=r(\frac{\omega_o-\omega}{t})=(2.0m)(\frac{7.0rad/s-13.0rad/s}{15s})=-0.8\frac{m}{s^2}$

Finally, you replace the values of aT and ac in the equation (1), in order to calculate the total acceleration:

$a=\sqrt{(14.0m/s^2)^2+(-0.8m/^2)^2}=14.022\frac{m}{s^2}$

The total acceleration of the ball is 14.022 m/s²

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3 years ago

The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a

sertanlavr [38]

Answer:

Electric field, E = $6.36\times 10^{6}\ V/m$

Explanation:

Given that,

The potential difference across the membrane, $\Delta V=0.063\ V$

The thickness of the membrane is, $\Delta x=9.9\times 10^{-9}\ m$

We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

$E=\dfrac{-\Delta V}{\Delta x}\\\\E=\dfrac{0.063\ V}{9.9\times 10^{-9}\ m}\\\\E=6.36\times 10^{6}\ V/m$

So, the magnitude of the electric field in the membrane is $6.36\times 10^{6}\ V/m$ .

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4 years ago

A water wave with a wavelength of 35.6 cm approaches a wall with a large opening in it. The hole begins to close. What size does

aleksley [76]

I think it might be 12.8cm.

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3 years ago

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