1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lidiya [134]
3 years ago
7

How far will a squirrel move is it has an average speed of 0.5 m/s and moves for 45 seconds?

Physics
1 answer:
butalik [34]3 years ago
5 0

Answer:

22.5meters

Explanation:

Step one:

Given data

Average speed = 0.5 m/s

time = 45 seconds

Required

The distance covered

Step two:

From Speed= distance/time

Distance= speed*time

Distance= 0.5*45

Distance= 22.5meters

You might be interested in
How many different atoms are there in a compound? ​
yKpoI14uk [10]

Answer:

2 or more atoms

Explanation:

yes yes yes yes yes yes yes yes

7 0
2 years ago
Read 2 more answers
In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallw
RSB [31]

Answer:

The coefficient of kinetic is

u_{k}=0.59

Explanation:

The forces in the axis 'x' and 'y' using law of Newton to find coefficient of kinetic friction

ΣF=m*a

ΣFy=W-N=0

ΣFy=Fn-Fu=m*a

F_{u} =u_{k} *N\\F_{N}=25N\\N=W\\N=3.5kg*9.8\frac{m}{s^{2} }=34.3N

F_{N}-F_{u}=m*a\\F_{N}-u_{k}*N=m*a\\u_{k}*N=F_{N}-m*a\\u_{k}=\frac{F_{N}-m*a}{N}

Now to find the coefficient can find the acceleration using equation of uniform motion accelerated

v_{f} ^{2}=v_{o}^{2}+2*a(x_{f}-x_{o})\\x_{o}=0\\v_{o}=0\\v_{f} ^{2}=2*a*x_{f}\\a=\frac{v_{f} ^{2}}{2*a*x_{f}}\\ a=\frac{(1.53\frac{m}{s} )^{2}}{2*0.91m}\\a= 1.28 \frac{m}{s^{2} }

So replacing the acceleration can fin the coefficient:

u_{k}=\frac{F_{N}-m*a }{N}\\u_{k}=\frac{25N-(3.5kg*1.28\frac{m}{s^{2}} }{34.3N} \\u_{k}=0.59

5 0
3 years ago
One hypothesis states that plate movement results from convection currents in the
brilliants [131]
I believe is A) Inner core
8 0
3 years ago
How much power is needed to lift the 200-N object to a height of 4 m in 4 s?
Vitek1552 [10]

Answer: 2000 watts

Explanation:

Given that,

power = ?

Weight of object = 200-N

height = 4 m

Time = 4 s

Power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

Power = (200N x 4m) / 4s

Power = 8000Nm / 4s

Power = 2000 watts

Thus, 2000 watts of power is needed to lift the object.

3 0
3 years ago
Susan gently pushes the tip of her finger against the eraser on her pencil and the pencil does not move. Which of the
pochemuha

Answer: D. ➡️⬅️

Explanation: I just knew the answer ;)

6 0
2 years ago
Other questions:
  • A rectangular billboard 5 feet in height stands in a field so that its bottom is 6 feet above the ground. A nearsighted cow with
    5·2 answers
  • This chart shows the global temperature anomaly (the difference of the expected temperature and the actual temperature) over a s
    8·2 answers
  • Consider two uniform solid spheres where one has twice the mass and twice the diameter of the other. The ratio of the larger mom
    15·1 answer
  • I will pick the branliest if answered these questions.
    14·2 answers
  • Select the correct answer.
    12·2 answers
  • Two children want to balance horizontally on a seesaw. The first child is sitting one meter to the left of the pivot point locat
    9·1 answer
  • How much force is needed to accelerate a 100 kg mass at a rate of 2.5 m/s^2
    5·1 answer
  • True or False: Graphs provide a good visual representation of the relationships between the factors investigated in an experimen
    11·1 answer
  • A sled is pushed with 30 Newtons and sliding friction is 10 Newtons find the net force on the sled​
    10·1 answer
  • A bat produces a sound at 17,250Hz and wavelength 0.019m. What is<br> the speed of the sound?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!