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Elina [12.6K]
3 years ago
8

A bicycle rider travels 50.0 km in 2.5 hours what is te bicyclist average speed

Physics
2 answers:
harina [27]3 years ago
5 0
Speed = distance /time
50,000/(2.5*60)
333.3 m/s
irina [24]3 years ago
3 0
If u divide the number you'll get on an average of 20km 
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NNADVOKAT [17]

Answer:

possibly A?

Explanation:

just feels right man

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3 years ago
A small economy car (low mass) and a limousine (high mass) are pushed from rest across a parking lot, equal distances with equal
Studentka2010 [4]

Answer:

The car that receives more kinetic energy is the small economy car.

Explanation:

K.E = 0.5*mv²

Where;

K.E is the kinetic Energy

M is the mass of an object

V is the velocity of the moving object

But F = m(v/t), from Newton's second law of motion

If equal forces were applied to the two cars, then the velocity of each car will be calculated as follows.

v = (Ft/m)

v² = (Ft/m)²

Substitute in the value of v² into Kinetic energy equation

K.E = 0.5*mv²

K.E = 0.5*m(Ft/m)² = (0.5*F²t²)/m

Also assuming equal distance, equal force and assuming equal time for both cars.

The above equation will reduce to, K.E = k/m

Where k = 0.5*F²t², which is equal in both cars.

Thus, Kinetic energy will depend only on the mass of each car.

From the above expression, Kinetic Energy received by each car is inversely proportional to the mass of the car.

A small economy car (low mass)  will receive more kinetic energy while a limousine (high mass) car will receive less kinetic energy.

Therefore, the car that receives more kinetic energy is the small economy car.

6 0
3 years ago
As a car accelerates its tires increase their angular velocity from 114 rad/s to 131 rad/s in 0.43 seconds. What is the angular
e-lub [12.9K]
I think it's 39.53

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5 0
3 years ago
Read 2 more answers
In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm, then what amount of elastic potential energy
myrzilka [38]
<h2>Answer:</h2>

4E

<h2>Explanation:</h2>

The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by

U = \frac{1}{2}kx^2               --------------------(i)

Where;

U = potential energy stored

k = spring constant of the material

x = elongation (extension or compression of the material).

<em>From the first statement;</em>

<em>when elongation (x) is 4cm, energy stored (U) is E</em>

<em>Substitute these values into equation (i) as follows;</em>

E = \frac{1}{2}k(4)^2

E = 8k

<em>Make k subject of the formula</em>    

k = \frac{E}{8}   [measured in J/cm]

<em>From the second statement;</em>

<em>It is stretched by 4cm.</em>

This means that total elongation will be 4cm + 4cm = 8cm.

The potential energy stored will be found by substituting the value of x = 8cm and k = \frac{E}{8} into equation (i) as follows;

U = \frac{1}{2}\frac{E}{8} (8)^2  

U = \frac{1}{2}{8E}

U = {4E}

Therefore, the potential energy stored will now be 4 times the original one.

3 0
3 years ago
A sheet of glass is coated with a 500-nm-thick layer of oil (n = 1.42).
tamaranim1 [39]

Answer:

a) <em>473.33 nm </em>

<em>b) 568 nm</em><em> and </em><em>406 nm</em>

<em>c) </em>bluish green and blue

Explanation:

a) As the light traverses the layer of oil it first reflects at the front surface of the oil. Here the index of refraction increases from that of air to that of the oil , so a phase change occurs.  The light then reflects from the rear surface of oil. The index of refraction increases from that of the oil to that of the glass , so again a phase change occurs.  Thus two phase changes occur.

In thin-film interference with 0 or 2 phase changes, condition for constructive interference is:

2t=mλ/n

So:

λ= 2tn/m

<em><u>For m=1</u></em>

λ=1420 nm

<em><u>For m=2</u></em>

λ=710 nm

<em><u>For m=3</u></em>

λ=473.33 nm

<em><u>For m=4</u></em>

λ=355 nm

<em>Thus the only wavelength in the visible spectrum </em><em>(400 - 700 nm)</em><em> that will give constructive interference is </em><em>473.33 nm </em>

b)

In thin-film interference with 0 or 2 phase changes, condition for destructive interference is:

2t=(m+1/2)λ/n=(2m+1)*λ/2n

so;

λ=4tn/(2m+1)

<em><u>For m=1</u></em>

λ=946.667 nm

<em><u>For m=2</u></em>

λ=568 nm

<em><u>For m=3</u></em>

λ=405.33 nm

<em><u>For m=4</u></em>

λ=315.56 nm

<em>Thus the wavelengths in the visible spectrum (</em><em>400 to 700 nm)</em><em> that will give destructive interference are </em><em>568 nm</em><em> and </em><em>406 nm</em>

<em>c) </em>The color of reflected light is bluish green  since the wavelength is 473.3 nm .  We know that the colors of reflected and transmitted light are complimentary to each  other.Thus the color of transmitted light  is blue (due  to the  combination of wavelengths 568 nm (green) and 406 nm (deep violet).

<em />

5 0
3 years ago
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