Question

Write the equation of a circle whose center is at the origin and contains the point (7, 0).

Answer 1

Radius of the circle = sqrt((7 - 0)^2 + (0 - 0)^2) = sqrt(7^2) = 7

Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the centre of the circle.

Required equation = (x - 0)^2 + (y - 0)^2 = 7^2
x^2 + y^2 = 49