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Vesnalui [34]
3 years ago
11

Dielectric breakdown in air occurs when the electric field is approximately 3 × 106 V/m.What would be the peak magnetic field in

an electromagnetic wave with this value for its peak electric field? in mT
Physics
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

10 mT

Explanation:

The relationship between electric field magnitude and magnetic field intensity in an electromagnetic wave is

E=cB

where

E is the magnitude of the electric field

c is the speed of light

B is the magnitude of the magnetic field

In this problem, we have

E=3\cdot 10^6 V/m is the electric field

c=3\cdot 10^8 m/s is the speed of light

Solving the equation for B, we find

B=\frac{E}{c}=\frac{3\cdot 10^6 V/m}{3\cdot 10^8 m/s}=0.01 T=10 mT

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Technician A says some compressor service procedures can be performed on the vehicle if space permits. Technician B says modern
stiv31 [10]

Answer:

Technicians A.

Explanation:

Since air compressor uses series of processes that turn incoming ambient air into a power source for tools and machinery. This means that air compressor has many different parts, and each of these parts must be maintained to ensure they function properly and optimally.

These are the basis when it comes to servicing a compressor

You need to change its oil

And clean its filters.

Inspected it's filters every three months, and have its filters replaced and connections tightened at least once every year.

To do all these can be performed on the vehicle if there is enough space just as Technician A said for the question context.

5 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. Nine joules of work is required to stret
natima [27]

Answer:

29.16 J

Explanation:

From Hook's law,

W = 1/2(ke²)..................... Equation 1

Where W = work done, k = Spring constant, e = extension.

Given: W = 9 J, e = 0.5 m.

Substitute into equation 1

9 = 1/2(k×0.5²)

Solve for k

k = 18/0.5²

k = 72 N/m.

The work done required to stretch the spring by additional 0.4 m is

W = 1/2(72)(0.4+0.5)²

W = 36(0.9²)

W = 29.16 J.

6 0
3 years ago
To teach you how to find the parameters characterizing an object in a circular orbit around a much heavier body like the earth.
Karolina [17]

Answer:

a)  T² = (\frac{4\pi ^2}{GM})  r³

b) veloicity the dependency is the inverse of the root of the distance

kinetic energy  depends on the inverse of the distance

potential energy dependency is the inverse of distance

angular momentum depends directly on the root of the distance

Explanation:

1) for this exercise we will use Newton's second law

            F = ma

in this case the acceleration is centripetal

            a = v² / r

the linear and angular variable are related

           v = w r

we substitute

           a = w² r

force is the universal force of attraction

           F = G \frac{m M}{r^2}

we substitute

         G \frac{m M}{r^2} = m w^2 r

         w² = \frac{GM}{r^3}

angular velocity is related to frequency and period

         w = 2π f = 2π / T

we substitute

            ( \frac{2\pi }{T} ) = \frac{GM}{r^3}

the final equation is

             T² = ()  r³

b) the speed of the orbit can be found

           v = w r

            v = \sqrt{\frac{GM}{r^3} } \ r

            v = \sqrt{\frac{GM}{r} }

in this case the dependency is the inverse of the root of the distance

Kinetic energy

           K = ½ M v²

           K = ½ M GM / r

           K = ½ GM² 1 / r

the kinetic energy depends on the inverse of the distance

Potential energy

          U =

          U = -G mM / r

dependency is the inverse of distance

Angular momentum

          L = r x p

for a circular orbit

           L = r p = r Mv

           L =

         L =

The angular momentum depends directly on the root of the distance

8 0
3 years ago
What is the resistance (R) when voltage is 179V and current is 5 Amps?
Evgesh-ka [11]

Answer:

R = 35.8 Ω

Explanation:

Recall Ohm's Law:

V = I * R

then R = V / I

in our case:

R = 179 V / 5 A = 35.8 Ω

3 0
3 years ago
A plane flying against a jet stream will travel faster than a plane traveling with a jet stream. Please select the best answer f
stepan [7]

"with the wind" is a tail-wind, and the speeds are added to get the groundspeed.

"against the wind" is a head-wind, and the windspeed is subtracted from the airspeed.

3 0
3 years ago
Read 2 more answers
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