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vladimir2022 [97]

2 years ago

11

What is the resistance (R) when voltage is 179V and current is 5 Amps?

1 answer:

Evgesh-ka [11]2 years ago

3 0

Answer:

R = 35.8 Ω

Explanation:

Recall Ohm's Law:

V = I * R

then R = V / I

in our case:

R = 179 V / 5 A = 35.8 Ω

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Answer:

The time taken is $t = 0.356 \ s$

Explanation:

From the question we are told that

The length of steel the wire is $l_1 = 31.0 \ m$

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The diameter of the wire is $d = 1.00 \ m = 1.0 *10^{-3} \ m$

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$t = t_s + t_c$

Where $t_s$ is the time taken to transverse the steel wire which is mathematically represented as

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$t_c$ is the time taken to transverse the copper wire which is mathematically represented as

$t_c = l_2 * [ \sqrt{ \frac{\rho_c * \pi * d^2 }{ 4 * T} } ]$

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So

$t_c = 17 * [ \sqrt{ \frac{7860 * 3.142* (1*10^{-3})^2 }{ 4 * 122} } ]$

$t_c =0.121$

So

$t = t_c + t_s$

$t = 0.121 + 0.235$

$t = 0.356 \ s$

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