1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotegsom [21]
3 years ago
10

A small ball is attached to one end of a spring that has an unstrained length of 0.169 m. The spring is held by the other end, a

nd the ball is whirled around in a horizontal circle at a speed of 3.15 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0131 m. By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?
Physics
1 answer:
Nadya [2.5K]3 years ago
5 0

The ball moves around in circular motion. The centripetal force keeping it in circular motion is given by:

F = mv²/r

F = centripetal force, m = mass of ball, v = velocity of ball, r = radius of motion

The force the spring exerts on the ball is given by:

F = kΔx

F = spring force, k = spring constant, Δx = change of spring length

The spring provides the centripetal force that keeps the ball in circular motion, so set the spring force equal to the centripetal force:

kΔx = mv²/r

Let's do some algebra:

m/k = rΔx/v²

Now if we attach the same spring to the ceiling with the ball still fixed to one end and let the ball hang in static equilibrium, the spring force would balance the ball's weight:

kΔx' = mg

k = spring constant, Δx' = new change in spring length, m = mass, g = gravitational acceleration

Let's do some more algebra:

Δx' = gm/k

Substitute m/k with our previous result, rΔx/v²:

Δx' = grΔx/v²

Given values:

g = 9.81m/s²

r = 0.169m + 0.0131m = 0.1821m

Δx = 0.0131m

v = 3.15m/s

Plug in the values and solve for Δx':

Δx' = 9.81(0.1821)(0.0131)/3.15²

Δx' = 0.0024m

You might be interested in
1. An object with a mass of m is thrown straight up near the surface of the earth. While the object is going up, the net force o
Vaselesa [24]

Answer:

C: equal to mg

Explanation:

in free-fall, gravity is always the net force on an object

5 0
3 years ago
1. What did the hard-boiled egg do when you lifted your finger? Describe your
jenyasd209 [6]

EXPLAINING : The raw egg keeps spinning after you touch it briefly because the liquid egg inside remains in motion, it's inertia is greater than that of the solid interior of the hardboiled egg. An object's momentum is its resistance to changing its state of motion; roughly "how hard it is to stop".

Answer : object's momentum

Please follow me me on youtube Cartoon View maker (US)

6 0
2 years ago
Which describes a function of the thalamus?
Natalka [10]

Answer:

figure it out bot

Explanation:

jhkhllkhlkh

4 0
2 years ago
Read 2 more answers
The position of an object is given by the equation x = 4.0t2 - 2.0 t - 4.5where x is in meters and t is in seconds. What is the
s344n2d4d5 [400]

Answer:

j

Explanation:

x = 4 t^2 - 2 t - 4.5

Position at t = 3 s

x = 4 (3)^2 - 2 (3) - 4.5 = 25.5 m

Velocity at t = 3 s

v = dx / dt = 8 t - 2

v ( t = 3 s) = 8 x 3 - 2 = 22 m/s

Acceleration at t = 3 s

a = dv / dt = 8

a ( t = 3 s ) = 8 m/s^2

When is the velocity = 0

v = 0

8 t - 2 = 0

t = 0.25 second

When is the position = 0

x = 0

4 t^2 - 2 t - 4.5 = 0

t = \frac{2 \pm \sqrt{4 + 72}}{8}

t = 1.4 second

8 0
3 years ago
A flat, 179 179 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.41 cm 2 4.41 cm2
Alecsey [184]

Answer:

The value of the magnetic field is  B =0.1423T

Explanation:

From the question we are told that

              The number of turns is  N = 179

               The area of the loop is A = 4.41cm^2 = \frac{4.41}{10000} = 0.000414m

                 The angle is  \theta  = 59^o

               The torque  is  \tau =2.25 * 10^{- 5} N

                The current is  I = 2.49\ mA

The torque acting on the current carry loop is  mathematically represented as

                     \tau = B * I * N * A * sin \theta

Where is the magnitude of the magnetic filed

Making B the subject

                     B= \frac{\tau}{I * N * A * sin\theta}

Substituting values

                    B = \frac{2.25*10^{-5}}{2.49*10^{-3} * 179 * 0.000414 * sin (59)}

                       =0.1423 T

4 0
3 years ago
Other questions:
  • While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
    8·1 answer
  • Whiat is quantum numbers describes the size and energy of an orbital?
    13·1 answer
  • 1. List one way mitosis and meiosis are the same and one way they are different.
    10·1 answer
  • Interactive Solution 6.39 presents a model for solving this problem. A slingshot fires a pebble from the top of a building at a
    11·1 answer
  • Most radiation exposure comes from
    8·2 answers
  • In a physics laboratory experiment, a coil with 250 turns enclosing an area of 14 cm2 is rotated in a time interval of 0.030 s f
    9·1 answer
  • A car is traveling at a constant speed of 40 m/s. When the driver accelerates, the car reaches a speed of 80 m/s in 6 seconds. W
    10·1 answer
  • AWARDING BRAINLIEST (~ ̄▽ ̄)~
    15·1 answer
  • Cho 3 điện trở, R1=R2=R3=10 ôm. Có nguồn điện 12V
    9·1 answer
  • how much energy would microraptor gui have to expend to fly with a speed of 10 m/sm/s for 1.0 minute?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!