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lyudmila [28]
4 years ago
5

Technician A says some compressor service procedures can be performed on the vehicle if space permits. Technician B says modern

compressors can be removed and reinstalled without discharging the rest of the system. Who is correct?
Physics
1 answer:
stiv31 [10]4 years ago
5 0

Answer:

Technicians A.

Explanation:

Since air compressor uses series of processes that turn incoming ambient air into a power source for tools and machinery. This means that air compressor has many different parts, and each of these parts must be maintained to ensure they function properly and optimally.

These are the basis when it comes to servicing a compressor

You need to change its oil

And clean its filters.

Inspected it's filters every three months, and have its filters replaced and connections tightened at least once every year.

To do all these can be performed on the vehicle if there is enough space just as Technician A said for the question context.

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The second-order bright fringe in a single-slit diffraction pattern is 1.35 mm from the center of the central maximum. The scree
Dafna11 [192]

Answer:

The wavelength is 754.2 nm.

Explanation:

Given that,

Diffraction pattern y= 1.35 mm

Width = 0.838 mm

Distance D= 75 cm

We need to calculate the wavelength

Using formula of diffraction pattern

y=\dfrac{m\lambda D}{d}

\lambda=\dfrac{yd}{mD}

Where, y = diffraction pattern

m = order

d = width

D = distance

Put the value into the formula

\lambda=\dfrac{1.35\times10^{-3}\times0.838\times10^{-3}}{2\times75\times10^{-2}}

\lambda=7.542\times10^{-7}\ m

\lambda=754.2\ nm

Hence, The wavelength is 754.2 nm.

4 0
3 years ago
Consider a coil lying in the plane of the screen and the external magnetic field pointing into the screen. As the external magne
Margaret [11]

Answer:

The direction of the induced magnetic field should be pointing towards the screen.

Explanation:

Because the magnetic field is decreasing, and if we use Len's law, the induced current will increase the external magnetic field. For this increase to occur, said magnetic field produced by the induced current must be pointing towards the screen.

6 0
4 years ago
How long does it take an airplane to fly 1200 miles if it maintains a speed of 300 miles per hour
sdas [7]

Answer:

The answer is

<h2>4 hrs</h2>

Explanation:

To find the time taken we use the formula

t =  \frac{d}{v}  \\

where

d is the distance covered

v is the velocity

t is the time

From the question

d = 1200 miles

v = 300 mi/hr

We have

t =  \frac{1200}{300}  =  \frac{12}{3}  \\

We have the final answer as

<h3>4 hrs</h3>

Hope this helps you

5 0
3 years ago
A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.923 g, q = 4.52 µC is locat
Anestetic [448]

Answer:

Q = -1.43\times 10^[-5} coulomb

Explanation:

Given data:

particle mass =  0.923 g

particle charge is 4.52 micro C

speed of particle 45.7 m/s

In this particular case, coulomb attraction will cause centrifugal force and taken as +ve and Q is taken as -ve

-\frac{Qq}{4\pi \epsilon r^2} = \frac{mv^2}{r}

solving for Q WE GET

Q = -\frac{mv^2}{r} \times r^2 \frac{4\pi \epsilon}{q}

Q = -mv^2\times r \frac{4\pi \epsilon}{q}

Q = - \frac{0.923\times 10^{-3} \times 45.7^2\times (22.6\times 10^{-2})} {4.52\times 10^{-6} \times 9\times 10^9}

where\frac{1}{4\pi \epsilon} = 9\times 10^9

Q = -1.43\times 10^[-5} coulomb

5 0
4 years ago
The box shown on the rough ramp above is sliding up the ramp.calculate the force of friction on the box
Anna [14]

We are given a box that slides up a ramp. To determine the force of friction we will use the following relationship:

F_f=\mu N

Where.

\begin{gathered} N=\text{ normal force} \\ \mu=\text{ coefficient of friction} \end{gathered}

To determine the Normal force we will add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction as shown in the following diagram:

In the diagram we have:

\begin{gathered} m=\text{ mass}_{} \\ g=\text{ acceleration of gravity} \\ mg=\text{ weight} \\ mg_y=y-\text{component of the weight. } \end{gathered}

Adding the forces in the y-direction we get:

\Sigma F_y=N-mg_y

Since there is no movement in the y-direction the sum of forces must be equal to zero:

N-mg_y=0

Now we solve for the normal force:

N=mg_y

To determine the y-component of the weight we will use the trigonometric function cosine:

\cos 40=\frac{mg_y}{mg}

Now we multiply both sides by "mg":

mg\cos 40=mg_y

Now we substitute this value in the expression for the normal force:

N=mg\cos 40

Now we substitute this in the expression for the friction force:

F_f=\mu mg\cos 40

Now we substitute the given values:

F_f=(0.2)(10\operatorname{kg})(9.8\frac{m}{s^2})\cos 40

Solving the operations:

F_f=15.01N

Therefore, the force of friction is 15.01 Newtons.

3 0
1 year ago
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