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4 years ago

8

The battery charger for an mp3 player contains a step-down transformer with a turns ratio of 1:24, so that the voltage of 120 v

available at a wall socket can be used to charge the battery pack or operate the player. what voltage does the secondary coil of the transformer provide? (no response) seenkey 5 v

1 answer:

miskamm [114]4 years ago

8 0

Considering that we are talking about a stepdown transformer, and a turn ration of 1:24

Then

Vsecondary coil = 120 V / 24 = 5V

(But lets remember that the power must be conserved in the transformer, so the voltage is 24 times less, but the current is 24 times higher)

It provides 5 volts to operate the player or charge the batteries

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a man counts 6 waves on a pond in 10 seconds. the distance between them is 40 cm. what is their speed?

gavmur [86]

Answer:

so a man counts 6 waves on a pound in 10 second

Explanation:

6×10 = 60

60/40

so the answer is3

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3 years ago

Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An

Vikentia [17]

Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>

Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
Then, the equation connecting parallax and the distance in parsec can be written as,

$d=\frac{1}{P}$

We can say that,

$dP=constant.\\thus,\\d_1P_1=d_2P_2$

<h3>How to solve the problem?</h3>

We have given that,

$d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?$

Thus, we can find the distance in parsecs as,

$d_2=\frac{d_1P_1}{P_2} =23.46 parsecs$

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

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6 0

2 years ago

An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti

shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

$I=F\Delta t$

where:

I is the impulse

F is the force exerted on the object

$\Delta t$ is the time during which the force is applied

For the object in this problem, we have

$F=106 N$ (force applied)

$\Delta t= 15.6 s$ (time interval)

Therefore, the impulse experienced by the object is:

$I=(106)(15.6)=1654 kg m/s$

3 0

3 years ago

The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a

katen-ka-za [31]

Answer:

1945.6 W

Explanation:

We are given that

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Time,t=37.5 min= $37.5\times 60=2250 s$

1 min=60 s

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Power,P=700 W

We have to find the his total metabolic power.

Power,= $P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W$

Where $g=9.8m/s^2$

Efficiency =25%

Therefore,Power,P'= $\frac{311.4}{0.25}=1245.6 W$

Total metabolic power=P+P'=700+1245.6=1945.6 W

7 0

3 years ago

g A wheel of diameter 8.0 cm has a cord of length 6.0 m wound around its periphery. Starting from rest, the wheel is given a con

sveticcg [70]

To solve this problem it is necessary to apply the equations related to the description of the tangential and angular movement.

The displacement where the speed and acceleration is related is given by the equation:

$x = v_0t+\frac{1}{2}at^2$

Where

$v_0 =$ Initial velocity (0 because start from rest)

t = time

a = Acceleration

We have angular acceleration but not tangential acceleration. Tangential acceleration can be obtained through the relationship

$a = r\alpha \rightarrow r = \frac{diameter}{2}$

$a = \frac{0.08}{2}(3)$

$a = 0.12m/s^2$

And we have also that the displacement is

$x = 6m$

Now replacing,

$x = v_0t+\frac{1}{2}at^2$

$6 = 0*t+\frac{1}{2}(0.12)t^2$

$6 = \frac{1}{2}(0.12)t^2$

$t = 10s$

Therefore will take the cord to unwind around 10s

7 0

3 years ago

Read 2 more answers