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3 years ago

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The gravitational pull of Jupiter is greater than the gravitational pull of Earth. How would adding a “JUPITER MODE” to the virt

ual activity change the results of Galileo’s experiment?

1 answer:

Vlad1618 [11]3 years ago

5 0

The Galileo's experiment is about Earth’s gravitational force have on objects of different masses.

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body

stellarik [79]

A) The change in internal chemical energy is $1.15\cdot 10^7 J$

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

$P=Fv$

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

$P=(80)(8.0)=640 W$

The energy output is related to the power by the equation

$P=\frac{E}{t}$

where:

P = 640 W is the power output

E is the energy output

$t = 30 min \cdot 60 = 1800 s$ is the time elapsed

Solving for E,

$E=Pt=(640)(1800)=1.15\cdot 10^6 J$

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

$\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J$

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

$E=1.15\cdot 10^7 J$

Here we want to find the time t' needed to convert an amount of chemical energy of

$E'=3.8\cdot 10^5 J$

So we can setup the following proportion:

$\frac{t}{E}=\frac{t'}{E'}$

And solving for t',

$t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min$

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0

2 years ago

If you took a white piece of plastic to a depth of 180 m, what color would it appear?.

SashulF [63]

Answer:

It would appear blue

Explanation:

3 0

2 years ago

two engines are turned on for 763 s at a moment when the velocity of the craft has x and y components of v0x = 6380 m/s and v0y

svet-max [94.6K]

Answer:

Explanation:

Given

initial velocity component of engines is

$v_0_x=6380 m/s$

$v_0_y=6770 m/s$

time period of engine running=763 s

Displacement in $x=4.50\times 10^6$

$y=7.27\times 10^6$

Using $s=ut+\frac{at^2}{2}$ in x and y direction

$x=v_0_x\times t+\frac{at^2}{2}$

$4.50\times 10^6=6380\times 763+\frac{a\times 763^2}{2}$

$4.50\times 10^6-4.86\times 10^6=\frac{a\times 763^2}{2}$

$a=-1.23 m/s^2$

In y direction

$y=v_0_y\times t+\frac{a't^2}{2}$

$7.27\times 10^6=6770\times 763+\frac{a\times 763^2}{2}$

$7.27\times 10^6-5.16\times 10^6=\frac{a\times 763^2}{2}$

$a=7.24 m/s^2$

x component $=-1.23 m/s^2$

y component $=7.24 m/s^2$

3 0

2 years ago

Read 2 more answers

Two objects having masses m1 and m2 are connected to each other as shown in the figure and are released from rest. There is no f

tankabanditka [31]

Answer: $m_1g$

Explanation:

Given

Two masses $m_1$ and $m_2$ is released and there is tension T in the string

Suppose a is the acceleration of the system

Therefore from Diagram

For $m_1$

$T-m_1g=m_1a$

$T=m_1(g+a)$ ------1

for m_2 body

$m_2g-T=m_2a$

$T=m_2(g-a)$ -------2

From above two Equation it is said that Tension is greater than m_1g and less than m_2g

$m_1g$

4 0

2 years ago

Read 2 more answers

The movement of water is like the flow of the electricity. Electricity must have a complete path for the flow. This movement is

Mama L [17]

The answer is current.

Current in the context of an electrical circuit is the flow of charge. Current is a quantity that is physical and can be measured. Current is defined as the rate of the flow charge past a certain point in a circuit. Current is expressed in Amperes which is equal to 1 coulomb/1second.

7 0

2 years ago