Answer:
Magnitude = 3.64 ×
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 × kilometers
turn = 70°
travel an additional = 2.7 × kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 × cos(70)
Qy= 2.7 × sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude =
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ =
tan စ = 0.9656
စ = 43.9°
Answer:
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction
Explanation:
In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:
(1)
v: speed of the proton = 9.9*10^5 m/s
q: charge of the proton = 1.6*10^-19C
B: magnetic field = ?
FB: magnetic force on the proton = 1.6*10^-13N
When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:
^j X (-^i) = -(-^k)=^k
To obtain the magnitude of the magnetic field you use:
The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction
Answer:
The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km
Explanation:
Given:
d = distance = 0.679 m
λ = wavelength of the light = 537 nm = 537x10⁻⁹m
dp = pupil diameter = 4.81 mm = 0.00481 m
Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?
For the separation of the peak from the central maximum it is:
In this case, the two small sources of the headlights have the same angle as the images that form inside the eye