2 years ago

The standard form of the equation of a parabola is x-y^2+10y+22.what is the vertex form of the equation?

Mathematics

1 answer:

neonofarm [45]2 years ago

4 0

x = y^2 + 10y + 22

Divide 10 by 2 to give 5 which becaoses the second term in the parentheses

x = (y + 5)^2 - 25 + 22

x = (y + 5)^2 - 3 Answer.

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Answer:

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2 years ago

Write the quadratic equation whose roots are -3 and 2 , and whose leading coefficient is 5

KiRa [710]

Step-by-step explanation:

Since, roots are - 3 & 2

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$5(x + 3)(x - 2) = 0 \\ \therefore \: 5( {x}^{2} - 2x + 3x - 6) = 0\\ \therefore \: 5( {x}^{2} + x - 6) = 0\\ \therefore \: 5 {x}^{2} + 5x - 30 = 0\: \\ is \: the \: required \: quadratic \: equation.$

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2 years ago

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3 years ago

Read 2 more answers

10. What is the distance between (8,7) and (3,-5)?

Anarel [89]

Answer:

distance between points=13 units

Step-by-step explanation:

distance between points= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

put $(x_1,x_2)$ =(8,7) and $(y_1,y_2)$ =(3,-5)

distance between points= $\sqrt{(3-8)^2+(-5-7)^2}$

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distance between points= $\sqrt{25+144}$

distance between points= $\sqrt{169}$

distance between points=13 units answer

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2 years ago

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Answer:

3/10

Step-by-step explanation:

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