During a reaction 24 cubic cm of carbon dioxide was given off. After 8 minutes no more gas was produced and the reaction was com
2 answers:
Answer:
Explanation:
Given parameters:
Volume of CO₂ = 24cm³
time taken for the reaction to complete = 8minutes.
Unknown:
rate of reaction
Soution
The reaction rate is a measure of speed of a chemical reaction. It is often calculated using the expression below:
Reaction rate =
Reaction rate = = 3cm³/min
In this reaction, 3cm³ of carbon dioxide were produced per minute
Answer:
Rate of the reaction = 3cm³/min
Explanation:
The rate of a reaction is essentially the speed at which the reaction proceeds. It is expressed in terms of the amount of reactants consumed or the amount of product formed.
Mathematically, it is the ratio of the change in concentration over a certain time period.
For the given reaction the initial concentration of carbon-dioxide = 0
Final concentration = 24 cm³
Change in concentration = Final - initial = 24 cm³
Time period = 8 min
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The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
<h3>How to find the empirical formula?</h3>Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus = 0.0293 mol
Moles bromine 6.99 g bromine=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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