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kramer
2 years ago
15

Helppppp asaapppppp plzzzzzz

Chemistry
1 answer:
Gala2k [10]2 years ago
7 0

Answer:

Alright the very first thing you need to do is balance the equation:

2HCl + Na2CO3 -----> 2NaCl + CO2 + H2O

Now we need to find the limiting reactant by converting the volume to moles of both HCl and Na2CO3.

Volume x Concentration/molarity = moles

0.235L x 0.6 M = 0.141 moles / molar ratio of 2 = 0.0705 moles of HCl

0.094L x 0.75 M = 0.0705 moles /molar ratio of 1  = 0.0705 moles of Na2CO3

Since both of the moles are equal, it means the entire reaction is complete (while the identification of limiting reactant may seem like an unnecessary step, it's quite essential in stoichiometry, so keep an eye out) and there is no excess of any reactant.

Now we know that the product we want to calculate is aqueous so, following the law of conservation of mass, we should add both volumes together to calculate how much volume we could get for NaCl.

0.235 + 0.094 = 0.329L of NaCl

Now we apply the C1V1 = C2V2 equation using the concentration and volume of Na2CO3 because it's molar ratio is one to one to NaCl (You can also use HCL, but you have to divide their moles by 2 for the molar ratio)  and the volume we just calculated for NaCl.

(0.75M) x (0.094L) = C2 x (0.329L)

Rearrange equation to solve for C2:

<u>(0.75M) x (0.094L)</u>  =  C2

    (0.329L)

C2 = 0.214 M (Rounded)

<u>When the reaction is finished, the NaCl solution will have a molarity concentration of 0.214 M.</u>

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Answer:

Once an enzymatic reaction is completed, the enzyme releases substrates.

Explanation:

The enzyme will always return to its original state at the completion of the reaction. One of the important properties of enzymes is that they remain ultimately unchanged by the reactions they catalyze. After an enzyme is done catalyzing a reaction, it releases its products (substrates).

5 0
2 years ago
Vitamin C has an empirical formula of C3H4O3 and a molecular mass of 176 amu. What is the molecular formula of vitamin C?
Vinvika [58]

Answer:

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3 0
3 years ago
Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form so
Reptile [31]

Answer:

Explanation:

The chemical reaction of the well-balanced equation is as follows:

\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}

The aforementioned reaction's ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}

3 0
3 years ago
What volume does 8.5 g NH₃ occupy at STP?
vesna_86 [32]
First, convert grams to moles by dividing 8.5 by the molar mass of NH₃ (N=14,H=1)
14+1+1+1=17
8.5/17=.5 moles NH₃
Multiply .5 by the conversion factor of moles to L (22.4)
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11.2 is just 11.21 rounded down, so your answer is C) 11.21 L
5 0
2 years ago
A 4.0 g sample of a solid changes from 20.0 ºC to 36.0 ºC upon addition of 25.0 cal of heat. What is the specific heat of this s
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Answer: c = 0.39 cal/g°C or

1.63 J/g°C

Explanation: To find the specific heat of the metal we will use the formula of heat which is Q= mc∆T.

We will derive for c, c = Q / m∆T

25.0 cal/ 4.0 g ( 36°C - 20°C)

= 0.39 cal / g°C

Or we can convert calories to joules.

0.39 cal x 4.184 J/ 1 cal

= 1.63 J /g°C

8 0
2 years ago
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