Answer: The empirical formula for the given compound is 
Explanation : Given,
Percentage of C = 38.8 %
Percentage of H = 16.2 %
Percentage of N = 45.1 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 38.8 g
Mass of H = 16.2 g
Mass of N = 45.4 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.
For Carbon = 
For Hydrogen = 
For Oxygen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : N = 1 : 5 : 1
Hence, the empirical formula for the given compound is 
Answer:
Zn(OH)2 + 2CH3COOH -----> Zn(CH3COO)2 + 2H2O
Explanation:
Zn(OH)2 + 2CH3COOH -----> Zn(CH3COO)2 + 2H2O
The P-H bond is polar and the molecule is asymmetric.
Non-polar bonds cannot produce polar molecules and symmetric bonds result in even distribution of charge, so no net charge is observed.
Explanation:
We are given the following diagram.
In this diagram we can see how the energy in the reaction changes over time. The energy of the products is greater than the energy of the reactants. That means that the products have won some energy. That represents an endothermic reaction where the reactants absorb energy from the surrounding to form the products.
Answer: D. Endothermic reaction.