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motikmotik
3 years ago
8

If the enthalpy value for a reaction is negative, what does that indicate about the reaction? Please explain how you got your an

swer
A) It’s endothermic and heat is absorbed by the system.
B) It’s exothermic and heat is absorbed by the system.
C) It’s endothermic and heat is released to the surroundings.
D) It’s exothermic and heat is released to the surroundings.
Chemistry
2 answers:
sukhopar [10]3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

When reactants absorb energy in a chemical reaction then products have more energy than the reactants. The value of \Delta H is positive for an endothermic reaction.

Whereas when reactants release energy in a chemical reaction then products have less energy than the reactants. The value of \Delta H is negative for an exothermic reaction.

Thus, we can conclude that if the enthalpy value for a reaction is negative, then it indicates that the reaction is exothermic and heat is released to the surroundings.

Elis [28]3 years ago
4 0

The answer is; D

Enthalpy is the system’s internal energy ( considering the product of its pressure and volume). When the enthalpy is negative, it means that the products have a lower energy level than the reactants - meaning the system has dispensed some energy into the environment.

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3 years ago
For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .
miss Akunina [59]

Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

[Na⁺] = 0.493 M

[Cl⁻] = 0.493 + 0.314 = 0.807 M

[NH₄⁺] = 0.314 M

The p-values are:

pNa = -log[Na⁺] = -log(0.493) = 0.307

pCl = -log[Cl⁻] = -log(0.807) = 0.093

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7 0
3 years ago
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