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motikmotik
4 years ago
8

If the enthalpy value for a reaction is negative, what does that indicate about the reaction? Please explain how you got your an

swer
A) It’s endothermic and heat is absorbed by the system.
B) It’s exothermic and heat is absorbed by the system.
C) It’s endothermic and heat is released to the surroundings.
D) It’s exothermic and heat is released to the surroundings.
Chemistry
2 answers:
sukhopar [10]4 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

When reactants absorb energy in a chemical reaction then products have more energy than the reactants. The value of \Delta H is positive for an endothermic reaction.

Whereas when reactants release energy in a chemical reaction then products have less energy than the reactants. The value of \Delta H is negative for an exothermic reaction.

Thus, we can conclude that if the enthalpy value for a reaction is negative, then it indicates that the reaction is exothermic and heat is released to the surroundings.

Elis [28]4 years ago
4 0

The answer is; D

Enthalpy is the system’s internal energy ( considering the product of its pressure and volume). When the enthalpy is negative, it means that the products have a lower energy level than the reactants - meaning the system has dispensed some energy into the environment.

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5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H
cricket20 [7]
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

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0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0
4 years ago
the combustion of a sample of butane C4H10 (lighter fluid ),produced 2.16 grams of water. 2C4H10 +13O2 ------->8CO2+10H2O how
ratelena [41]
I think this is learned in chemistry do you have any notes that can help
7 0
3 years ago
Use the periodic table to select which type of bond is present and which of the listed properties is most
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Answer:

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3 0
3 years ago
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Plug in the initial conditions on the left, then the final/new on the right, and solve for the unknown:

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V₂ = (165(2.5)(373))/(298(600))

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