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motikmotik
4 years ago
8

If the enthalpy value for a reaction is negative, what does that indicate about the reaction? Please explain how you got your an

swer
A) It’s endothermic and heat is absorbed by the system.
B) It’s exothermic and heat is absorbed by the system.
C) It’s endothermic and heat is released to the surroundings.
D) It’s exothermic and heat is released to the surroundings.
Chemistry
2 answers:
sukhopar [10]4 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

When reactants absorb energy in a chemical reaction then products have more energy than the reactants. The value of \Delta H is positive for an endothermic reaction.

Whereas when reactants release energy in a chemical reaction then products have less energy than the reactants. The value of \Delta H is negative for an exothermic reaction.

Thus, we can conclude that if the enthalpy value for a reaction is negative, then it indicates that the reaction is exothermic and heat is released to the surroundings.

Elis [28]4 years ago
4 0

The answer is; D

Enthalpy is the system’s internal energy ( considering the product of its pressure and volume). When the enthalpy is negative, it means that the products have a lower energy level than the reactants - meaning the system has dispensed some energy into the environment.

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Why must the ph ammonia buffer solution be stored and dispensed in the fume exhaust hood?
Vadim26 [7]

On the other hand ammonia is a very dangerous chemical which has a pungent smell and effect the eyes of the user. Thus it kept always in the fume exhaust hood for storing and dispensing function.  

The  pH of ammonia buffer contains ammonium hydroxide (NH₄OH) and a salt of ammonia with a  strong acid like (HCl) which produces, ammonium chloride (NH₄Cl) mixture. The evaporation rate of ammonia is so high at room temperature thus on opening of the buffer solution the ammonia get evaporated very fast and the concentration of ammonia decreases which affect the pH of the buffer solution.

Thus the reason to put ammonia buffer in fume hood is explained.


7 0
3 years ago
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
What is the energy of a microwave photon that has a frequency of 9.86 x 1012 Hz?
BlackZzzverrR [31]

Answer:

6.533 × 10^-21J

Explanation:

The energy of the microwave photon can be calculated using:

E = hf

Where;

E = energy of photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency (9.86 x 10^12 Hz)

Hence, E = hf

E = 6.626 × 10^-34 × 9.86 x 10^12

E = 65.33 × 10^(-34 + 12)

E = 65.33 × 10^(-22)

E = 6.533 × 10^-21J

The energy of the microwave photon is

6.533 × 10^-21J

5 0
3 years ago
Which gas law states that the pressure of a gas decreases when volume is increased and the temperature is unchanged
Nesterboy [21]

Answer: Boyle's law

Explanation: It states that pressure of a gas is inversely proportional to the volume of a gas at constant temperature.

P∝\frac{1}{V}       at constant temperature

or If the pressure of gas is decreased, the volume increases if the temperature is unchanged and If the pressure of gas is increased, the volume decreases if the temperature is unchanged.

P_1V_1=P_2V_2

3 0
4 years ago
Read 2 more answers
The volume, in liters, occupied by 2.50 moles of N2 gas.<br><br><br> calculate at STP
kondaur [170]

Answer: The volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =0.0821Latm/Kmol

T =temperature =273K  (at STP)

V=\frac{nRT}{P}

V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L

Thus the volume occupied by 2.50 moles of N_2 gas at STP is 56.0L

6 0
4 years ago
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