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motikmotik
4 years ago
8

If the enthalpy value for a reaction is negative, what does that indicate about the reaction? Please explain how you got your an

swer
A) It’s endothermic and heat is absorbed by the system.
B) It’s exothermic and heat is absorbed by the system.
C) It’s endothermic and heat is released to the surroundings.
D) It’s exothermic and heat is released to the surroundings.
Chemistry
2 answers:
sukhopar [10]4 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

When reactants absorb energy in a chemical reaction then products have more energy than the reactants. The value of \Delta H is positive for an endothermic reaction.

Whereas when reactants release energy in a chemical reaction then products have less energy than the reactants. The value of \Delta H is negative for an exothermic reaction.

Thus, we can conclude that if the enthalpy value for a reaction is negative, then it indicates that the reaction is exothermic and heat is released to the surroundings.

Elis [28]4 years ago
4 0

The answer is; D

Enthalpy is the system’s internal energy ( considering the product of its pressure and volume). When the enthalpy is negative, it means that the products have a lower energy level than the reactants - meaning the system has dispensed some energy into the environment.

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Answer:

[2 ]Na+[2 ]H2O -> [ 2] NaOH + [1]H2

5 0
3 years ago
What is the SI base unit for length?
sp2606 [1]

The SI base unit for length is meter.

In order to make smaller measurements, you can use the centi-, milli-, micro-, etc. prefixes.

When you want to reference larger measurements, you can use the kilo-, mega-, giga- and prefixes such as those.

5 0
3 years ago
Consider the following chemical reaction in a small volume of solution. According to LeChatelier’s Principle, which perturbation
stiks02 [169]

Answer:

Decreasing the temperature will shift the equilibrium leftwards towards reactants.

Explanation:

Hello!

In this case, since the reaction between chromate anions and hydrogen ions yields dichromate anions, water and heat, we can infer this is an exothermic reaction by which heat is released (remember in endothermic reactions heat is absorbed as a reactant), it means that considering the LeChatelier’s which states that increasing the temperature of an exothermic reaction shifts the equilibrium leftwards since heat is a product, otherwise (decreasing the temperature) the equilibrium will be shifted rightwards.

Therefore, decreasing the temperature is the perturbation that will shift the equilibrium leftwards towards the reactants.

Best regards!

7 0
3 years ago
Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0
3 years ago
When the metal was placed in the calorimeter, its temperature dropped to the equilibrium temperature. Calculate the change in te
MAVERICK [17]

Answer:

1st one= -79.6

2nd one= -80

3rd one= -81.2

Explanation:

Good luck!

5 0
3 years ago
Read 2 more answers
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