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STatiana [176]
3 years ago
5

Compare erosion and deposition.

Physics
2 answers:
pishuonlain [190]3 years ago
6 0
Erosion makes rocks wear away and deposition deposits sediment.
hoa [83]3 years ago
6 0
Erosion is the move ment of sedement deposison is the depoentment of sediment
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Phantasy [73]

Answer:

gggggggggggggggggggggggggggggggggg

Explanation:

6 0
3 years ago
A bobsled has a momentum of 3000 kg•m/s to the east. After the rider gives it a push, its momentum increases to 5500 kg•m/s to t
Archy [21]
Impulse, denoted as J, is defined by the change in momentum. Since we have our initial and our final, we can solve for the change in momentum.

J = p_{f} - p_{0} = 5500 - 3000 = 2500

J = 2500 kg*m/s
7 0
3 years ago
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If Inability to maintain posture while standing still would indicate a problem with which equilibrium receptor?
Alekssandra [29.7K]
The inability to maintain posture while standing still would indicate a problem with the static equilibrium receptors. S<span>tatic equilibrium receptors provide information about body position relative to the force of gravity: standing upright v. being upside done. Hope this helps.</span>
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3 years ago
This problem explores the behavior of charge on realistic (i.e. non-ideal) insulators. We take as an example a long insulating r
frez [133]

Answer:

A) weakly attracted

B) negative charge on end A with B remaining almost neutral

C) strongly repelled

Explanation:

A)

  • As the negatively charged ball is brought close to the end A of the road, positive charges on this end try to move away from there, leaving a small negative charge in this end, as they are not free to move as in a conductor.
  • As a consequence of this, the end A of the road will be weakly attracted by the negatively charged ball.

B)

  • After several contacts between the ball and the end A of the rod, an appreciable quantity of negative charge has been deposited in the end A, repelling positive charges towards the end B.
  • However, as the rod is an insulator, positive charges can't travel massively to the end B, so it remains almost neutral.

C)

  • After repeated contacts that have deposited a significative negative charge on the end A (which can't distribute evenly as in a conductor), when the ball (negatively charged) is brought close to this end of the rod, as both bodies have the same type of charge, they will be strongly repelled each other.
3 0
4 years ago
Will give Brianliest answer. help.
BARSIC [14]

Answer:

v₁ = 1.78 m/s

Explanation:

We can use the law of conservation of momentum here, as follows:

m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2

where,

m₁ = mass of first object = 4.5 kg

m₂ = mass of second object = 6.2 kg

u₁ = initial speed of first (smaller) mass = 16 m/s

u₂ = initial speed of second (larger) mass = 0 m/s

v₁ = final speed of first (smaller) mass = ?

v₂ =  final speed of second (larger) mass = 10 m/s

Therefore,

(4.5\ kg)(16\ m/s)+(6.2\ kg)(0\ m/s)=(4.5\ kg)(v_1)+(6.2\ kg)(10\ m/s)\\70\ kgm/s - 62\ kgm/s = (4.5\ kg)v_1\\\\v_1 = \frac{8\ kgm/s}{4.5\ kg}\\\\

<u>v₁ = 1.78 m/s</u>

6 0
3 years ago
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