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2 years ago

What is Obama's last name? PLZ PLZ PLZ THIS IS 500% OF MY GRADE PLS HELP PLS

Physics

2 answers:

kherson [118]2 years ago

5 0

Answer:

Explanation:

B A R A K

O B A M A

kotegsom [21]2 years ago

4 0

Answer:

Barack Hussein Obama II

Explanation:

I think

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A 310-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper

Marizza181 [45]

Answer:

t = 166 years

Explanation:

In order to calculate the amount of years that electrons take to cross the complete transmission line. You first calculate the drift speed of the electrons by using the following formula:

$v_d=\frac{I}{nqA}$ (1)

I: current on the wire = 1,010A

n: free charge density = 8.50*10^28 electrons/m^3

A: cross-sectional area of the transmission line = π*r^2

r: radius of the cross-sectional area = 2.00cm = 0.02m

You replace the values of the parameters in the equation (1):

$v_d=\frac{1,010A}{(8.50*10^{28}electron/m^3)(1.6*10^{-19}C)(\pi (0.02m)^2)}\\\\v_d=5.9*10^{-5}\frac{m}{s}$

Next, you use the following formula:

$t=\frac{x}{v_d}$ (2)

x: length of the line transmission = 310km = 310,000m

You replace the values of vd and x in the equation (2):

$t=\frac{310,000m}{5.9*10^{-5}m/s}=5.24*10^9s$

Finally, you convert the obtained t to seconds

$t=5.24*10^9s*\frac{1\ year}{3.156*10^7s}=166.03\ years$

The electrons take approximately 166 years to travel trough the complete transmission line

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