Answer:
Filtering <span>is best laboratory technique to separate a solid from a liquid to recover the liquid.
Explanation:
A solid particles present in liquids can be separated from liquid by utilizing a membrane having pores large enough to allow the liquid molecules to pass through and small enough to stop the solid particles from crossing.
Example:
Tea Filters are used to separate Tea from the grounds.
Kidney is an excellent example of Biological Filter.
</span><span>Whatman Cellulose Filter Paper used in Chemistry Labs.</span>
To find the chemical formula of an ionic compound, the first step is to find the charge of the 2 ions. As given already, the charge of sodium ion is 1+, and carbonate ion has a charge of 2-. We can picture it like that: Sodium ion loses 1 electron and carbonate ion gains 2.
The next step is to find how the 2 ions can lose and gain electrons equally. In this case, since each Na ion only loses 1 electron, it cannot satisfy the need of one carbonate ion, since they need 2, not 1. Therefore, 2 Na ions can cover the need of one carbonate ion. So, the ratio of Na to CO3 ion should be 2:1.
Now just combine the 2 ions, positive one at the front, which makes it NaCO3, make sure you do not add the charge and notice that CO3 is a molecule itself so do not remove the 3. Now because the ratio is 2:1, so the final formula is Na2CO3, no need to add 1 if the ratio is 1.
Your answer should be Na2CO3.
Answer:
<h2>0.44 </h2>
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ { H_3O}^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7B%20H_3O%7D%5E%7B%2B%7D%5D)
From the question we have

We have the final answer as
<h3>0.44</h3>
Hope this helps you
X element can give 3 electrons, and ions X³⁺ can be formed.
Phosphate ion - (PO4)³⁻,
So compound will have formula X³⁺(PO4)³⁻,
XPO4
Answer:
(c) an aqueous solution of CO2 exhibits dipole-dipole forces between solute and solvent
Explanation:
Co2 is a non-polar molecule.
It is actually shown to be O=C=O.
When dissolved in water to get aqueous solution.
Dipole on water molecule can induce dipole on CO2.
This entails that we should have dipole-induced dipole forces when we have a mixture or solvent and solute.
But the given statement states dipole dipole forces between solute and solvent.
Hence the statement is false.