Answer:
C.) 2
Explanation:
The pH equation is:
pH = -log[H⁺]
In this equation, [H⁺] is the molarity of the acid. In this case, the acid is HCl. Molarity can be found using the equation:
Molarity (M) = moles / volume (L)
Since you were given moles and volume, you can find the molarity of HCl.
Molarity = moles / volume
Molarity = 0.01 moles / 1.00 L
Molarity = 0.01 M
Now, you can plug the molarity of the acid into the pH equation.
pH = -log[H⁺]
pH = -log[0.01]
pH = 2
Answer:
0.2007 nm
3.57 cm
0.01478 g
8280000 pg
Explanation:
1)200.7 pm
1 picometer is equal to 0.001 nanometer.
1 nm = 1000 pm
200.7 pm× 1 nm / 1000 pm = 0.2007 nm
2)0.000357 hm
1 hectometer is equal to 10,000 centimeter.
1 hc = 10,000 cm
0.000357 hc× 10,000 cm / 1 hc = 3.57 cm
3) 14.78 mg
1 gram is equal to 1000 milligram.
1 g = 1000 mg
14.78 mg × 1 g/1000 mg = 0.01478 g
4)8.280 µg
1 microgram is equal to 10⁶ picogram.
1 µg = 1000000 pg
8.280 µg× 10⁶ pg/ 1µg = 8.280×10⁶ pg or 8280000 pg
The given question is incomplete. The complete question is :
It takes 151 kJ/mol to break an iodine-iodine single bond. Calculate the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon. Be sure your answer has the correct number of significant digits.
Answer: 793 nm
Explanation:
The relation between energy and wavelength of light is given by Planck's equation, which is:

where,
E = energy of the light = 151 kJ= 151000 J (1kJ=1000J)
N= moles = 1 = 
h = Planck's constant = 
c = speed of light = 
= wavelength of light = ?
Putting in the values:


Thus the maximum wavelength of light for which an iodine-iodine single bond could be broken by absorbing a single photon is 793 nm