KBr + H2O = KOH + Br2 + H2
So we know that we need a 2 on the left of kbr so it would equal the right Br.
=2KBr
now put a 2 in front of KOH since we need a 2k on right side
Now we put a 2 infront of H2O which wil make 4 h's and 2 o's
2h2o
now it is balanced
2KBr + 2H2O = 2KOH + Br2 + H2
Answer:
- <em>Brønsted-Lowry acid: HNO₂</em>
- <em>Brønsted-Lowry base: NH₃</em>
- <em>Conjugate acid: NH₄⁺</em>
- <em>Conjugate base: NO₂⁻</em>
Explanation:
The equation is:

<em>Brønsted-Lowry acids</em> are H⁺ donors.
<em>Brønsted-Lowry bases</em> are H⁺ acceptors.
Thus, on the left side, <em>HNO₂</em> is the acid and <em>NH₃ </em>is the base.
The <em>conjugate acids</em> and <em>conjugate bases</em> are on the right side of the equation.
The <em>conjugate acid</em> is the spieces that is formed after a base accepts the proton; thus it is <em>NH₄⁺</em>. A <em>conjugate acid</em> contains one more H atom and one more + charge than the base that formed it.
The <em>conjugate base</em> is the species that is formed after the acid donates its proton; thus, <em>NO₂⁻</em> is the <em>conjugate base</em>. A <em>conjugate base</em> contains one less H atom and one more - charge than the acid that formed it.
Summarizing:
- Brønsted-Lowry acid: HNO₂
Answer:
<h3>here you go :)</h3>
Explanation:
<h3>Increasing the concentration of reactants generally increases the rate of reaction because more of the reacting molecules or ions are present to form the reaction products. ... When concentrations are already high, a limit is often reached where increasing the concentration has little effect on the rate of reaction.
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