12x - 4x = 8 + 3 - 3
8x = 8
X = 1
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
Answer:
x - 3 = 0
Step-by-step explanation:
You can realise it plotting the points.
Or you can use : ( x - x1 ) / ( y - y1 ) = ( x1 - x2 ) / ( y1 - y2 )
where ( x1 , y1 ) and ( x2 , y2 ) are the given points.
12/24 simplifies to 1/2, seeing as 12 is half of 24. :) Your answer is C.
