Ask question

Ask question

All categories

3 years ago

14

Determine the current I flowing through a solenoid, if the magnetic flux inside its core is found to be 1.30 10-4 Wb. The radius

of the solenoid is 11.0 cm and the number of turns per meter is 235.

1 answer:

inna [77]3 years ago

7 0

Answer: The current I flowing through a solenoid is 11.6A

Explanation: Please see the attachments below

You might be interested in

After being pushed and released, a 50 kg crate slides across a factory floor. Friction on the sliding crate is 200 N, what is th

saveliy_v [14]

F = ma
200 = 50 * a
4 = a

Therefore acceleration is 4ms^-2

6 0

3 years ago

A force of 825 N is needed to push a car across a parking lot. Two students push a car 35 m. How much total work is done?

MaRussiya [10]

<h2>Answer :</h2><h2 />

Work is the amount of energy transferred. As per the formula

Work = Force x Distance [moved toward the direction of the force]

So as per the formula

<u>Solution : </u>

Force = 825 N

Distance = 35 m

Work = 825 (n) x 35 (m)

Work = 28875 Joules

<h2 />

6 0

3 years ago

a loaded sack of total mass is 1000 gramme falls down from the floor of a lorry 200cm high, calculate the workdone by the gravit

Helen [10]

Answer:

W = 20 J

Explanation:

Given that,

The mass of a loaded sack, m = 1000 g = 1 kg

It falls down from the floor of a lorry 200 cm high, h = 2 m

We need to find the work done by the gravity. The work done by an object under the action of gravity is given by :

W = mgh

Substitute all the values,

W = 1 × 10 × 2

= 20 J

Hence, the required work done by gravity is equal to 20 J.

8 0

3 years ago

You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb

Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is $I = 15\ kg \frac{m}{s}$

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity $V_{x}$ = 20 $\frac{m}{s}$

Velocity after collision $V_{-x}$ = - 10 $\frac{m}{s}$

(A). Impulse of the net force on the ball during its collision with wall is

$I = m (V_{x} - V_{-x})$

I = 0.5 × (20 + 10)

$I = 15\ kg \frac{m}{s}$

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

$F = \frac{I}{T}$

Where F = Force

I = impulse & t = time interval = 0.001 sec

$F = \frac{15}{0.001}$

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

8 0

3 years ago

Choose the correct words from the box to complete the definition of resistance.

zzz [600]

Answer:

Opposition of passing a electric circuit

6 0

3 years ago