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TiliK225 [7]
3 years ago
9

If 16 moles of al react with 3 moles of S8 how many moles of Al2 S3 will be formed

Chemistry
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

8 moles

Explanation:

Al reacts with S_8 to produce Al_2S_3 as

Al+S_8\rightarrow Al_2S_3

The balanced chemical equation is

16Al+3S_8\rightarrow 8Al_2S_3

In the reaction, 16 moles of Al react with 3 moles of S_8 to produce 8 moles of Al_2S_3.

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They catch fire very easily.

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Use Boyle's Law to solve the following problem. A 400 mL sample of a gas is at 10
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Answer:

v2 = 100 Ml OR 0.1 Liters

Explanation:

(400 Ml) (10 atm) = (v2) (40 atm)

4000 = 40v2

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How many moles are in 1.806 x 1024 molecules of bromine?
Pepsi [2]
<h3>Answer:</h3>

2.999 mol Br

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

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  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.806 × 10²⁴ molecules Br

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 1.806 \cdot 10^{24} \ molecules \ Br(\frac{1 \ mol \ Br}{6.022 \cdot 10^{23} \ molecules \ Br} ) = 2.999 mol Br

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

Our final answer is already in 4 sig figs, so there is no need to round.

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Number 4 : solid product
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Fill in the coefficients that will balance the following reaction:
vfiekz [6]

6NaC₂H₃O₂   +  Fe₂O₃   →   2Fe(C₂H₃O₂)₃  +  3Na₂O

Explanation:

Given equation;

      NaC₂H₃O₂   +  Fe₂O₃   →   Fe(C₂H₃O₂)₃  +  Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

      aNaC₂H₃O₂   +  bFe₂O₃   →   cFe(C₂H₃O₂)₃  +  dNa₂O

a, b, c and d are the coefficients that  will balance the equation.

 conserving Na;    a  = 2d

                       C:     2a  = 6c

                       H:     3a  = 9c

                       O;      2a + 3b  = 6c + d

                       Fe:     2b = c

let a = 1

    solving:

      2a = 6c

       2(1) = 6c

          c = \frac{2}{6}  = \frac{1}{3}

      2b = c

          b = \frac{1}{2}  x \frac{1}{3} = \frac{1}{6}

     d = 2a + 3b - 6c = 2(1 ) + (3 x\frac{1}{6}  )  - (6  x  \frac{1}{3}) = \frac{1}{2}

Now multiply through by 6

  a = 6, b = 1, c = 2 and d = 3

             

                6NaC₂H₃O₂   +  Fe₂O₃   →   2Fe(C₂H₃O₂)₃  +  3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

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