After the first (main) earthquake, other smaller shocks may occur at times for:

1 answer:

4 0

Aftershocks can after the first (main) earthquake, other smaller shocks may occur at times for several weeks to months or even for few years.

Explanation:

Aftershocks are a series of lower intensity earthquakes which occur following a main higher intensity earthquake in the same location but at a short rupture distance from the main fault line.

The number and intensity of aftershocks decrease with time. Aftershocks result from changes in the internal stress taking place suddenly after the principle change by the main earthquake.

The rocks near the major fault line cause aftershocks. The damage caused by aftershocks also varies with the intensity of the main earthquake and sometimes aftershocks can bring down buildings or trees which were already weakened by the main earthquake

You might be interested in

A scientist evaluates its livestock and determines which livestock it is

Rina8888 [55]

Any animals look for steangth mostly because the offspring can probobly onther trait is looks. The male will try to impess the female.

4 0

3 years ago

What is the mass of 1.59 moles of Ca(CIO3)2

salantis [7]

329.10 g is the mass of 1.59 moles of Ca(ClO3)2

6 0

3 years ago

Ammonia and gaseous hydrogen chloride combine to form ammonium chloride. NH3+HCL->NH4CL

Hatshy [7]

The balanced chemical equation would be as follows:

NH3+HCL->NH4CL

For this, we assume these gases are ideal gases so we can use the equation PV=nRT. We first calculate the number of moles of each reactants. We do as follows:

PV=nRT
1.02 (4.21) = n (0.08206)(27+273.15)
n = 0.17 mol NH3 ------->consumed completely and therefore the limiting reactant

PV=nRT
0.998 (5.35 L) = n (0.08206)(26+273.15)
n = 0.22 mol HCl

what mass of NH4Cl(s) will be produced?
0.17 mol NH3 (1 mol NH4Cl / 1 mol NH3 ) = 0.17 mol NH3

which gas is the limiting reactant?
NH3 gas

which gas is present in excess?
HCl gas

4 0

3 years ago

What is correct about solubility of substances?

Svet_ta [14]

I think it should be A

7 0

3 years ago

What pressure would be required to take 100.0 ml of a gas at 103.0 kPa and squish it down to 2.00 ml

melamori03 [73]

Answer:

5150 kPa

Explanation:

Given that,

Initial volume, V₁ = 100 mL

Initial pressure, P₁ = 103 kPa

Final volume, V₂ = 2 mL

We need to find the new pressure of the gas. The relation between the pressure and the volume of gas is given by :

$P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{103\times 100}{2}\\\\P_2=5150\ kPa$

So, the new pressure is 5150 kPa.

7 0

3 years ago