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3 years ago

A scientist evaluates its livestock and determines which livestock it is

1 answer:

4 0

Any animals look for steangth mostly because the offspring can probobly onther trait is looks. The male will try to impess the female.

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If 16g of <img src="https://tex.z-dn.net/?f=CH_%7B4%7D" id="TexFormula1" title="CH_{4}" alt="CH_{4}" align="absmiddle" class="la

sammy [17]

43.56 grams of are produced if 16g of CH4 reacts with 64g of O2.

Explanation:

Balance equation for the reaction:

CH4 + 2O2⇒ CO2 +2H2O

Data given : mass of CH4 =16 grams atomic mass = 16.04 grams/mole

mass of water 36 gram atomic mass = 18 grams/moles

mass of CO2=? atomic mass = 44.01 grams/mole

number of moles = $\frac{mass}{atomic mass of one mole}$ equation 1

number of moles in CH4

n = $\frac{16}{16.04}$

= 0.99 moles

Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.

From the equation

1 mole of CH4 gave 1 mole of CO2

O.99 moles of CH4 will give x moles of CO2

$\frac{1}{1}$ = $\frac{x}{0.99}$

x = 0.99 moles of carbon dioxide

grams of CO2 = number of moles x atomic mass

= 0.99 x 44.01

= 43.56 grams of CO2 is produced.

4 0

3 years ago

an unknown molecule is found to consist of 24.2% carbon by mass, 4.0% hydrogen by mass and the remaining mass is due to chlorine

Paha777 [63]

Answer:

C3 H6 Cl 3

Explanation:

C -24.2%

H - 4.0%

Cl - (100-24.2 - 4.0)=73.8 %

We can take 100g of the substance, then we have

C -24.2 g

H - 4.0 g

Cl - 73.8 g

Find the moles of these elements

C -24.2 g/12.0 g/mol =2.0 mol

H - 4.0 g/1.0 g/mol = 4. 0 mol

Cl - 73.8 g/ 35.5 g/mol = 2.1 mol

Ratio of these elements gives simplest formula of the substance

C : H : Cl = 2 : 4 : 2 = 1 : 2 : 1

CH2Cl

Molar mass (CH2Cl) = 1*12.0 +2*1.0 + 1*35.5 = 49.5 g/mol

Real molar mass = 150 g/mol

real molar mass/ Molar mass (CH2Cl) = 150 /49.5=3

So, Real formula should be C3 H6 Cl 3.

4 0

4 years ago

Read 2 more answers

How are the circulatory systems in animals and plants alike

yKpoI14uk [10]

Ok, so the circulatory system in plants and animals is like a method of transport. Both plants and animals use this to transport waste and nutrition.

-Agarvated

(hope this helps, have a great day!)

8 0

3 years ago

The rate of a hypothetical reaction involving L and M is found to double when the concentration of L is doubled and to increase

Semmy [17]

Answer: $Rate=k[L]^1[M]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$L+M\rightarrow products$

$Rate=k[L]^x[M]^y$ (1)

k= rate constant

x = order with respect to L

y = order with respect to M

n =( x+y)= Total order

a) If [L] is doubled, the reaction rate will increase by a factor of 2:

$2\times Rate=k[2L]^x[M]^y$ (2)

b) If [M] is doubled, the reaction rate will increase by a factor of 4:

$4\times Rate=k[L]^x[2M]^y$ (3)

Dividing 2 by 1:

$\frac{2\times Rate}{Rate}=\frac{k[2L]^x[M]^y}{k[L]^x[M]^y}$

$2=2^x$

$x=1$

Dividing 3 by 1

$\frac{4\times Rate}{Rate}=\frac{k[L]^x[2M]^y}{k[L]^x[M]^y}$

$4=2^y$

$2^2=2^y$

$y=2$

Thus rate law is: $k[L]^1[M]^2$

4 0

4 years ago

How many milliliters of a stock solution of 6.20 M HNO3 would you have to use to prepare 0.130 L of 0.470 M HNO3?

Mandarinka [93]

Answer:

9.85

Explanation:

M1V1 =M2V2

6.20×v1= 0.470×0.130

v1 = ( 0.470 × 0.130 ) ÷ 6.20

v1 = 0.0098 L × 1000

V1 = 9.8 ml

6 0

3 years ago