Answer:
is the maximum velocity of this reaction.
Explanation:
Michaelis–Menten 's equation:
![v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}](https://tex.z-dn.net/?f=v%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7BK_m%2B%5BS%5D%7D%3Dk_%7Bcat%7D%5BE_o%5D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7BK_m%2B%5BS%5D%7D)
![V_{max}=k_{cat}[E_o]](https://tex.z-dn.net/?f=V_%7Bmax%7D%3Dk_%7Bcat%7D%5BE_o%5D)
v = rate of formation of products =
[S] = Concatenation of substrate
= Michaelis constant
= Maximum rate achieved
= Catalytic rate of the system
= Initial concentration of enzyme
We have :


![[S]=0.110 mol/dm^3](https://tex.z-dn.net/?f=%5BS%5D%3D0.110%20mol%2Fdm%5E3)
![v=V_{max}\times \frac{[S]}{K_m+[S]}](https://tex.z-dn.net/?f=v%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7BK_m%2B%5BS%5D%7D)
![1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}](https://tex.z-dn.net/?f=1.15%5Ctimes%2010%5E%7B-3%7D%20mol%2Fdm%5E3%20s%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B0.110%20mol%2Fdm%5E3%7D%7B%5B%280.045%20mol%2Fdm%5E3%29%2B%280.110%20mol%2Fdm%5E3%29%5D%7D)
![V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s](https://tex.z-dn.net/?f=V_%7Bmax%7D%3D%5Cfrac%7B1.15%5Ctimes%2010%5E%7B-3%7D%20mol%2Fdm%5E3%20s%5Ctimes%20%5B%280.045%20mol%2Fdm%5E3%29%2B%280.110%20mol%2Fdm%5E3%29%5D%7D%7B0.110%20mol%2Fdm%5E3%7D%3D1.620%5Ctimes%2010%5E%7B-3%7D%20mol%2Fdm%5E3%20s)
is the maximum velocity of this reaction.
Answer: The resultant pressure is 3.22 atm
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
(At constant volume and number of moles)
where,
= initial pressure of gas = 2.79 atm
= final pressure of gas = ?
= initial temperature of gas = 273K
= final temperature of gas = 315 K

Thus the resultant pressure is 3.22 atm
Answer:
More/ Alot? I think is what you are looking for?
Explanation:
It will definitely have some but I'm not sure on what word you are looking for.
Answer:
Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal
Explanation:
The molecular formula of mannoheptulose is C₇H₁₄O₇.
The structure is as shown in the attachment below.
Number of C-C bonds present in mannoheptulose = 6
Number of C-H bonds present in mannoheptulose = 8
Since the each C-C bond contains 76 Kcal of energy,
Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal
Also, since each C-H bond contains 91 Kcal of energy;
amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal
Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal