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Cerrena [4.2K]
3 years ago
5

Which of these is true about a pH meter?

Chemistry
2 answers:
Goryan [66]3 years ago
7 0
The pH meter measure the concentration of the hydrogen(+) ion, and the concentration of Hydroxide(-). Hydrogen is acidic, Hydroxide is basic.

The answer is D.
Fantom [35]3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

An electronic device which is used to measure hydrogen ion activity is known as a pH meter.

That is, a pH meter is useful in detecting or knowing the acidity (due to H^{+} ions) or alkalinity (due to OH^{-} ions) of a solution.

Thus, we can conclude that out of the given options it is true about a pH meter that it can be used in any acid-base titration.

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how many moles of water are in 1.23 x 10^18 water molecules? I need the answer in scientific notation ?
Ann [662]

Answer:

Moles=2.04×10^(-6)

Explanation:

No. Of moles=no. Of particles/ Avogadro's no

(Where no. Of particles may be atoms molecules or compounds)

Moles=1.23×10^18/6.022×10^23

Moles=0.204×10^(-5)

Moles=2.04×10^(-6)

8 0
3 years ago
Put the substance in a 25 mL beaker.
kkurt [141]

Answer: 1. Liquid

2. oily

3. no (not a solid)

Explanation:

5 0
4 years ago
Read 2 more answers
Anyone could help me out?
Hoochie [10]

1.4 mg/dL = 0.014 g/L

Explanation:

Milligrams per deciliter to grams per liter

There is 1000 grams of mg/dL of 1 g/L

8 0
3 years ago
Read 2 more answers
a sample of a compound contains 60gC and 5.05gH.it molar mass is 78.12g/mol what is the compound molecular formula
elena55 [62]
(60)/(60+5.05)=.922367 C
1-0.922367=0.07763259 H
(0.922367)(78.12)=72.05534204 C
(0.07763259)(78.12)=6.06 H
72.05534204/(12.01)=6 C
6.06/1.01=6 H
Empirical= CH
Molecular=C6H6
5 0
3 years ago
The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur
vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

T_1 = 100^0 C = 100+273 = 373 \ K \\ \\  T_2 = 113^0 C = 113 + 273 = 386 \ K

R_1 = \dfrac{1}{7}

R_2 = \dfrac{1}{49}

Thus; \dfrac{R_2}{R_1} = 7

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})

1.9459 = \dfrac{Ea}{8.314}* 9.0292  *10^{-5}

1.9459*8.314 = Ea * 9.0292*10^{-5}

16.1782126= Ea * 9.0292*10^{-5}

Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

T_2 = 386 \  K  \\ \\T_1 = (89.8 + 273)K = 362.8 \ K

In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})

In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})

In (\dfrac{R_2}{R_1}) = 0.00357

\dfrac{R_2}{R_1}= e^{0.00357}

\dfrac{R_2}{R_1}= 1.0035

where ;

R_2 = \dfrac{1}7{}

R_1 = \dfrac{1}{t}

Now;

\dfrac{t}{7}= 1.0035

t = 7.0245 mins

Therefore; it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

4 0
3 years ago
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