C) elements from the top left and the top right of the periodic table
Answer:
light energy is a form of electromagnetic radiations of a wavelength, which can be seen by the human eye.
Answer:
5.5 moles of given substance.
Explanation:
The given problem can be solved by using the Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
Solution:
3.311 ×10²⁵ / 6.022 × 10²³ = moles
5.5 moles of given substance.
Answer:
Option C . CO2(g) + H2O(g)
Explanation:
When hydrocarbon undergoes combustion, carbon dioxide (CO2) and water (H2O) are produced.
C2H4(g) + O2(g) —› CO2(g) + H2O(g)
Thus, the product of the unbalanced combustion reaction is:
CO2(g) + H2O(g)
Thus, we can balance the equation as follow:
C2H4(g) + O2(g) —› CO2(g) + H2O(g)
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balanced by putting 2 in front of CO2 as shown below:
C2H4(g) + O2(g) —› 2CO2(g) + H2O(g)
There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balanced by putting 2 in front of H2O as shown below:
C2H4(g) + O2(g) —› 2CO2(g) + 2H2O(g)
There are a total of 6 atoms of O on the right side and 2 atom on the left side. It can be balanced by putting 3 in front of O2 as shown below:
C2H4(g) + 3O2(g) —› 2CO2(g) + 2H2O(g)
Thus, the equation is balanced.
Answer:
A. Theoretical yield = 3.51g
B. %yield = 75%
Explanation:
The balanced equation for the reaction is given below:
C2H4 + 3O2 —> 2CO2 + 2H2O
Molar Mass of O2 = 16 x 2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96
Molar Mass of H20 = (2x1) + 16 = 18g/mol
Mass of H2O from the balanced equation = 2 x 18 = 36g
A. From the equation,
96g of O2 produced 36g of H2O
Therefore, 9.35g of O2 will produce = (9.35 x 36)/96 = 3.51g of H2O
Therefore,theoretical yield of water (H2O) = 3.51g
B. Theoretical yield = 3.51
Actual yield = 2.63g
%yield =?
%yield = Actual yield/Theoretical yield x 100
%yield = 2.63/3.51
%yield = 75%
