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34kurt
3 years ago
14

During which change of state does the thermal energy of a substance increase

Chemistry
1 answer:
ryzh [129]3 years ago
3 0
Vaporization takes place when the particles in a liquid gain enough energy (thermal energy) to form a gas.
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Compute 6.28×1013+7.30×1011.
Simora [160]
6.28×1013+7.30×1011 this =13741.94
6 0
4 years ago
The respiration rate of a goldfish is measured. The goldfish is then placed in cold water and the respiration rate is measured a
Ivenika [448]

Answer:

Temperature of the water

Explanation:

In every study, there must be independent and dependent variables. An independent variable is the variable that is changed in order to obtain a response. In this case, the temperature of the water is being changed, the response in this experiment is the respiration rate of the goldfish.

Thus the respiration rate of the goldfish is the dependent variable because it is controlled by the temperature of the water and changes accordingly.

Summarily, the independent variable is the temperature of the water while the dependent variable is the respiration rate of the goldfish.

4 0
3 years ago
___Al+NaOH=>__Na3AlO3+H2
MaRussiya [10]

Explanation:

<em><u>2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2</u></em>

<em><u>...</u></em>

8 0
3 years ago
What do greenhouse gases (CO2) do to the atmosphere?
Alborosie

Answer:

they causes climate change by trapping heat and also they contribute to respiratory diseases from smog and air pollution

4 0
3 years ago
Read 2 more answers
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
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