During which change of state does the thermal energy of a substance increase

Is anybody good in Chemistry that can help me with this?

sesenic [268]

Answer:

just replace the 9 mole with 3.68 g of Al .

I think it will help you.

5 0

3 years ago

Will give brainliest! if 32.0 g of hcl is to be diluted to make a 4.80 m solution, how much water should be added?

nadezda [96]

The required volume of water is 0.18 liters.

<h3>What is molarity?</h3>

Molarity of any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V

Moles of solute will be calculated as:

n = W/M, where

W = given mass of HCl = 32g

M = molar mass of HCl = 36.4g/mol

n = 32 / 36.4 = 0.88 mole

Given molarity of solution = 4.80M

On putting all values in the above equation, we get

V = (0.88) / (36.4) = 0.18 L

Hence required volume of water is 0.18L.

To know more about volume & concentration, visit the below link:

brainly.com/question/26762947

#SPJ1

6 0

2 years ago

The maximum level of lead allowed in drinking water is 15 mg/kg. What is this concentration in units of parts per million?

Alecsey [184]

15 ppm
1.5 × 10-2 ppm
1.5 × 104 ppm
3.1 ppm
1.5 × 10-2 ppm

6 0

3 years ago

In a chemistry laboratory, a student filled a 10.0 L container with two (2) different gases. The

alexgriva [62]

Answer:

$P_N=1.33atm\\\\P_O=0.67atm$

$P_T=2.00 atm$

Explanation:

Hello.

In this case, the first step is to compute the moles of nitrogen and oxygen given their initial P, T and V conditions via the ideal gas equation:

$n_{N}=\frac{P_{N}V_{N}}{RT} =\frac{2.00atm*24.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{N}=2.144molN\\\\n_{O}=\frac{P_{O}V_{O}}{RT} =\frac{2.00atm*12.0L}{0.082\frac{atm*L}{mol*K}*273K}\\ \\n_{O}=1.072molO$

After that, since the total volume now, once the mixture is formed is the addition between the initial volumes (12.0 L + 24.0 L) is 36.0 L, the partial pressure of each gas turns out:

$P_N=\frac{2.144mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_N=1.33atm\\\\P_O=\frac{1.072mol*0.082\frac{atm*L}{mol*K}*273K}{36.0L}\\\\P_O=0.67atm$

Thus, the final total pressure is:

$P_T= P_N+P_O=1.33atm+0.67atm\\\\P_T=2.00 atm$

Best regards.

3 0

3 years ago

Many hospitals use radioisotopes for diagnosis and treatment or in palliative care. Three radioisotopes used in medicine are giv

ehidna [41]

The question is incomplete, here is the complete question:

Many hospitals use radioisotopes for diagnosis and treatment, or in palliative care (relief of symptoms such as pain). Some radioisotopes used in medicine are listed below. Write the isotope symbol for each radioisotope. Replace the question marks with the proper integers. Replace the letter X with the proper element symbol.

a) Iodine-131:

b) Iridium-192:

c) Samarium-153:

Answer:

For a: The isotopic representation of the given isotope is: $_{53}^{131}\textrm{I}$

For b: The isotopic representation of the given isotope is: $_{77}^{192}\textrm{Ir}$

For c: The isotopic representation of the given isotope is: $_{62}^{153}\textrm{Sm}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For the given options:

Option a: Iodine-131

The atomic number of iodine is 53 and the atomic mass of the given isotope is 131. The chemical symbol for iodine element is 'I'

Hence, the isotopic representation of the given isotope is: $_{53}^{131}\textrm{I}$

Option b: Iridium-192

The atomic number of iridium is 77 and the atomic mass of the given isotope is 192. The chemical symbol for iridium element is 'Ir'

Hence, the isotopic representation of the given isotope is: $_{77}^{192}\textrm{Ir}$

Option c: Samarium-153

The atomic number of samarium is 62 and the atomic mass of the given isotope is 153. The chemical symbol for iridium element is 'Sm'

Hence, the isotopic representation of the given isotope is: $_{62}^{153}\textrm{Sm}$

6 0

3 years ago