Answer:
The work done on the object by the force in the 5.60 s interval is 40.93 J.
Explanation:
Given that,
Force 
Mass of object = 2.00 kg
Initial position 
Final position 
Time = 4.00 sec
We need to calculate the work done on the object by the force in the 5.60 s interval.
Using formula of work done


Put the value into the formula




Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.
The answer to your question is Protons!
Explanation:
Formula to calculate angular acceleration is as follows.

or, 
Putting the given values into the above formula as follows.

=
= 0.326 
Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326
.