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Verizon [17]
3 years ago
13

What was anton van leeuwenhoek famous for

Physics
1 answer:
monitta3 years ago
3 0

Answer:

He is known as the first microbiologist and also “the Father of Microbiology” because he was the first to observe bacteria underneath a microscope. He made many other significant discoveries in the field of biology and also made important changes to the microscope.

Explanation:

hope this helps. and if it did pls mark brainliest :)

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Look at this picture of a whale shark. Which question about the whale shark is nonscientific?
Sergeeva-Olga [200]

I need the picture to answer the question

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3 years ago
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A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m
Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

Put the value into the formula

W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0
2 years ago
Explain why the several different types of microscopes are all neccassary?
Sphinxa [80]

Answer:

  • The different types of microscopes are all necessary because not all experiments require the same level of magnification. ... All microscopes allow visualization of samples that are too small to be viewed by the naked eye.

Explanation:

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7 0
2 years ago
The Periodic Table of Elements is organized by the number of:
QveST [7]
The answer to your question is Protons!
5 0
3 years ago
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The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an
Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

   \Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t

or,      \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

Putting the given values into the above formula as follows.

    \alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}

                = \frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}    

                = 0.326 rad/s^{2}

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 rad/s^{2}.

5 0
3 years ago
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