<span>First let's find the acceleration required in the barrel to speed the ball up from 0 to 83 m/s in a distance of 2.17 m. We know the force the cannon exerts on the cannonball is 20000 N; if we can find this acceleration then we can use F = ma to find the mass.
We can find the acceleration using one of the kinematic equations of motion. We have:
u = initial speed = 0 m/s
v = final speed = v0 = 83 m/s
d = distance = 2.17 m
a = acceleration = ?
v² = u² + 2ad. Since u = 0, this reduces to v² = 2ad and rearranges to a = v²/2d = 83²/2*2.17 = 83²/4.34 = 1587.327 m/s².
Now F = ma, so m = F/a = (20000N)/(1587.327 m/s²) = 12.6 kg.
For part 2, use the Range Equation:
If R is the horizontal distance the cannonball travels,
v = v0 = the initial velocity = 83 m/s
g = acceleration due to gravity - 9.8 m/s²
x the launch angle relative to the horizontal, then
R = (v²sin(2x))/g.
So R = (83²sin(2*37))/9.8
= (6889sin74)/9.8 = 676 m.
So the target ship is 676 m away.</span>
Close together but are able to slide past one another
I can't see the screw (if you'll pardon the expression), so I don't know a thing about it, and can't answer the question. There's no given information in the question.
The equivalent of Newton's second law for rotational objects is given by:
where
is the net torque acting on the object
is its moment of inertia
is its angular acceleration
For a hoop rotating around its perpendicular axis, the moment of inertia is
where m is the mass and r the radius. By using the data of the wheel, m=0.750 kg and r=33.0 cm=0.33 m, we find
and since the torque is
, the angular acceleration of the wheel is
Answer:
The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.
Explanation:
Strain is defined mathematically as follows .
strain = Δ L/ L
Δ L is change in length of a wire when some force is applied on it to stretch it along its length and L is original length of a wire .
Stress is The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.