the answer is J. 3,900,000 got it right on the test
Answer:
the planet Earth is a good example
Answer:
0.239 T
Explanation:
Applying,
F = Bvqsin∅................ Equation 1
Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.
make B the subject of the equation
B = F/(vqsin∅)................. Equation 2
From the question,
Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)
Constant: q = 1.602 x 10⁻¹⁹ C
Substitute into equation 2
B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)
B = 1.15×10⁻¹³/(4.806×10⁻¹³)
B = 0.239 T.
Hence the magnetic field = 0.239 T
Answer:
Explanation:
Acceleration of gravity on the surface of
Neptune is given
g' = G M/R^2,
where M is the planet's mass.
M g' will be the apparent weight registed at the poles.
G is the universal constant of gravity
The "apparent weight" at the equator will be
reduced from M g' by the centripetal force M
R w^2, where w is the rotational angular
velocity in radians/s), which you can deduce
from the 16 hour length of a day.
