Answer:
The correct option is;
∠AQS ≅ ∠BQS when AS = BS
Step-by-step explanation:
Given that AQ is equal to BQ. When AS is drawn congruent to BS, we have;
QS is congruent to SQ by reflective property
Therefore;
The three sides of triangle QAS are congruent to the three sides of triangle QBS, from which we have;
∠AQS and ∠BQS are corresponding angles, therefore;
∠AQS ≅∠BQS because corresponding angles of congruent triangles are also congruent.
Best Answer:<span> </span><span>So first we need both areas, then we can relate them, and then divide the circle by the square:
A(circle) = πr^2
A(square) = L*W or (2r)*(2r) which is (2r)^2
For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square.
Ratio: (πr^2)/(4r^2) = π/4</span>
8 because 24 divided by 3 is eight
