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34kurt
4 years ago
15

Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2​

Chemistry
1 answer:
svlad2 [7]4 years ago
6 0

Hey there!

NaBr + Cl₂ → NaCl + Br₂

First balance Na.

One on the left, one on the right: already balanced.

Next balance Br.

One on the left, two on the right. Add a coefficient of 2 in front of NaBr.

2NaBr + Cl₂ → NaCl + Br₂

Lastly balance Cl.

Two on the left, one on the right. Add a coefficient of 2 in front of NaCl.

2NaBr + Cl₂ → 2NaCl + Br₂  

This is our final balanced equation.

Hope this helps!

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Determine the relative formula mass of glucose (C6H12O6) using the periodic table below.
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Answer:

D. 180.1 g/mol

Explanation:

Add up each of the masses of the elements in glucose and multiply them by the subscript number.

Carbon: 12.01 * 6 = 72.06

Hydrogen: 1.008 * 12 = 12.096

Oxygen: 16.00 * 6 = 96

72.06 + 12.096 + 96 = 180.156 g/mol ≈ 180.1 g/mol

*Molecular masses vary depending on which measurement / periodic table you use, so expect to be within a range, not exactly the same. My answer was closer to 180.2 g/mol, but it's still acceptable.

3 0
4 years ago
Read 2 more answers
Write the IUPAC substitutive name of the major product when 2-methylbut-1-ene reacts with: a) HCl b) HBr in the presence of pero
aleksandr82 [10.1K]

Answer and Explanation:

The IUPAC substitutive name of the major product when 2-methylbut-1-ene reacts are as follows

a) HCl = 2-chloro-2-methylbutane

b) HBr in the presence of peroxides =  1-bromo-2-methylbutane

c) H2O/ H2SO4 (dilute sulfuric acid)  = 2-methylbutane-1,2-diol

d)BH3-THF followed by basic hydrogen peroxide =  2-methylbutan-1-ol

e) Chlorine in water =  2-chloro-2-methylbut -1 -ol

f) Bromine in carbon tetrachloride =  1,2- dibromo-2-methybutane

g) H2 in the presence of a metal catalys = isopentane or 2- methyl butane

8 0
3 years ago
Which compounds below share the same empirical formula?
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6 0
3 years ago
1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the
Maurinko [17]

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that,  A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by,   Q = msΔT.

where Q = heat absorbed

            m = mass of the substance

            s = specific heat of substance

          ΔT  = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m =  \frac{Q}{s(T_{2} -T_{1}) }

⇒ m = \frac{50.1}{0.900(15.5)} = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g

5 0
3 years ago
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