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34kurt
4 years ago
15

Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2​

Chemistry
1 answer:
svlad2 [7]4 years ago
6 0

Hey there!

NaBr + Cl₂ → NaCl + Br₂

First balance Na.

One on the left, one on the right: already balanced.

Next balance Br.

One on the left, two on the right. Add a coefficient of 2 in front of NaBr.

2NaBr + Cl₂ → NaCl + Br₂

Lastly balance Cl.

Two on the left, one on the right. Add a coefficient of 2 in front of NaCl.

2NaBr + Cl₂ → 2NaCl + Br₂  

This is our final balanced equation.

Hope this helps!

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) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that t
sergeinik [125]

Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

m_{calcite}=15.4448g-12.4631g=2.9817g

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL

Thus, the density of the calcite sample will be:

\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

Learn more:

  • brainly.com/question/12001845
  • brainly.com/question/11242138

Regards!

6 0
2 years ago
If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus
timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = R=\frac{V}{1.34 min}

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

R'=\frac{V}{t'}

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

\frac{R}{R'}=\sqrt{\frac{M'}{M}}

\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}

t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0
3 years ago
can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ
mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

7.SL

8.CL

9.SL

10.CL

Explanation:

HOPE ITS HELP

5 0
3 years ago
How does High Density Polyethylene (HDPE) can be improved of the life cycle of consumers use?
dybincka [34]

Answer:

Idk about this question sry

7 0
4 years ago
Which test is used to detect nitrogen, sulfur, and halogens?
galben [10]

Lassaignes test should be the answer

7 0
3 years ago
Read 2 more answers
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