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3 years ago

Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2

Chemistry

1 answer:

svlad2 [7]3 years ago

6 0

Hey there!

NaBr + Cl₂ → NaCl + Br₂

First balance Na.

One on the left, one on the right: already balanced.

Next balance Br.

One on the left, two on the right. Add a coefficient of 2 in front of NaBr.

2NaBr + Cl₂ → NaCl + Br₂

Lastly balance Cl.

Two on the left, one on the right. Add a coefficient of 2 in front of NaCl.

2NaBr + Cl₂ → 2NaCl + Br₂

This is our final balanced equation.

Hope this helps!

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So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

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As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

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Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2​

Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2