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34kurt
3 years ago
15

Balance the following chemical equation:NaBr+Cl2, –NaCl+Br2​

Chemistry
1 answer:
svlad2 [7]3 years ago
6 0

Hey there!

NaBr + Cl₂ → NaCl + Br₂

First balance Na.

One on the left, one on the right: already balanced.

Next balance Br.

One on the left, two on the right. Add a coefficient of 2 in front of NaBr.

2NaBr + Cl₂ → NaCl + Br₂

Lastly balance Cl.

Two on the left, one on the right. Add a coefficient of 2 in front of NaCl.

2NaBr + Cl₂ → 2NaCl + Br₂  

This is our final balanced equation.

Hope this helps!

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2 years ago
Pls help me I don’t know what to dooooo
Ivan
Molarity = moles of solute/volume of solution in liters.

The solute here is NaCl, of which we have 46.5 g. To calculate the molarity of an NaCl solution, we need to know the number of moles of NaCl. To convert from grams to moles, we divide the mass by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of Na and Cl: 23 amu + 35 amu = 58 amu. For our purposes, we can regard amu as equivalent to grams/mole.

(46.5 g)/(58 g/mol) = 0.8017 moles NaCl.

Now that we know both the number of moles of our NaCl solute and the volume of the solution, we can calculate the molarity:

(0.8017 moles NaCl)/(2.2 L) = 0.364 M.
5 0
3 years ago
1
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Answer:

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6 0
3 years ago
How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?
weeeeeb [17]

Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

\text{Moles of }Ca(OH)_2=0.0788mol

Therefore, the number of moles of solute Ca(OH)_2 is, 0.0788 moles.

7 0
3 years ago
You are making a 0.2M solution of sodium acetate in the lab. Sodium acetate has a molecular mass of 82.03 g/mol. How many g of s
lyudmila [28]

Answer: The answer can be found on CHEG

Explanation:

7 0
3 years ago
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