Hey there!
It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.
In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

Thus, the density of the calcite sample will be:

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL
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Regards!
Answer:
The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.
Explanation:
Let the volume of the helium gas be = V
Time taken by the helium gas = t = 1.34 min
Effusion rate of helium gas = 
If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

Using Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

Molar mass of helium gas = M = 4 g/mol
Molar mass of ammonia gas = M' = 17 g/mol



The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.
Answer:
Idk about this question sry
Lassaignes test should be the answer