What is the magnitude of the torque about his shoulder due to the weight of the ball and his arm if he holds his arm straight ou
t to his side, parallel to the floor?
1 answer:
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Answer:
1) d
2) 5 m/s
3) 100
Explanation:
The equation of position x for a constant acceleration a and an initial velocity v₀, initial position x₀, time t is:
(i)
The equation for velocity v and a constant acceleration a is:
(ii)
1) Solve equation (ii) for acceleration a and plug the result in equation (i)
(iii)
(iv)
Simplify equation (iv) and use the given values v = 0, x₀ = 0:
(v)
2) Given v₀= 3m/s, a=0.2m/s², t=10 s. Using equation (ii) to get the final velocity v:
3) Given v₀=0m/s, t₁=10s, t₂=1s and x₀=0. Looking for factor f = x(t₁)/x(t₂) using equation(i) to calculate x(t₁) and x(t₂):