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marin [14]
3 years ago
12

Two golf balls with the same mass were hit at the same time. Golf ball A went a shorter distance than golf ball B. What could be

a reason that this happened?
Golf ball B experienced more friction.
Golf ball A experienced less friction.
Golf ball B was hit with a weaker force.
Golf ball A was hit with a weaker force.
Physics
2 answers:
Firdavs [7]3 years ago
7 0

Answer:

Golf ball A was hit with a weaker force

Explanation:

Golf ball B went a larger distance than golf ball A, so we could think friction affected golf ball A rather than golf ball B. That is why the first two choices are wrong.

The strongest forced applied made golf ball B go further.

GrogVix [38]3 years ago
5 0
Golf ball a was hit with a weaker force
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The superheroine Xanaxa, who has a mass of 68.1 kg , is pursuing the 75.3 kg archvillain Lexlax. She leaps from the ground to th
Alexandra [31]

The concept required to solve this problem is associated with potential energy. Recall that potential energy is defined as the product between mass, gravity, and change in height. Mathematically it can be described as

U = mg\Delta h

Here,

\Delta h = Change in height

m = mass of super heroine

g = Acceleration due to gravity

The change in height will be,

\Delta h = h_f - h_i

The final position of the heroin is below the ground level,

h_f = -16.1m

The initial height will be the zero point of our system of reference,

\Delta h = -16.1m-0m

\Delta h = -16.1m

Replacing all this values we have,

U = mg\Delta h

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U = -10744.81J

Since the final position of the heroine is located below the ground, there will net loss of gravitational potential energy of 10744.81J

4 0
3 years ago
Cool facts about satellites ???
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7 0
2 years ago
A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 18.5 kg, and the
meriva

Answer:

a.2.86 m/s^2

b.1058 N

Explanation:

We are given that

Mass of each dog,M=18.5 kg

Mass of sled with rider,m=250 kg

a.Average force,F=185 N

\mu_s=0.14

g=9.8 m/s^2

By Newton's second law

8F-f=(8M+m)a

a=\frac{8F-f}{8M+m}=\frac{8(185)-(0.14)(9.8)(250)}{8(18.5)+250}

a=2.86 m/s^2

b.By Newton's second law

T=ma+\mu_s mg

Substitute the values

T=250\times 2.86+0.14(250)(9.8)=1058 N

Hence, the force in the coupling between the dogs and the sled=1058 N

8 0
3 years ago
What is the acceleration of an 24 kg object that applies a force of 130N?
WITCHER [35]

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

6 0
2 years ago
The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
Monica [59]
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. </span><span>The equation for </span>gravitational potential energy<span> is GPE = mgh. 

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
Read 2 more answers
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