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marin [14]
3 years ago
12

Two golf balls with the same mass were hit at the same time. Golf ball A went a shorter distance than golf ball B. What could be

a reason that this happened?
Golf ball B experienced more friction.
Golf ball A experienced less friction.
Golf ball B was hit with a weaker force.
Golf ball A was hit with a weaker force.
Physics
2 answers:
Firdavs [7]3 years ago
7 0

Answer:

Golf ball A was hit with a weaker force

Explanation:

Golf ball B went a larger distance than golf ball A, so we could think friction affected golf ball A rather than golf ball B. That is why the first two choices are wrong.

The strongest forced applied made golf ball B go further.

GrogVix [38]3 years ago
5 0
Golf ball a was hit with a weaker force
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Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat.  Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.

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A rigid, nonconducting tank with a volume of 4 m3 is divided into two unequal parts by a thin membrane. One side of the membrane
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The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

To find the answer, we need to know about the thermodynamic processes.

<h3>How to find the final temperature of the gas?</h3>
  • Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
  • In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
  • The membrane is raptured without applying any external force, thus, dW=0.
  • We have the first law of thermodynamic expression as,

                                dU=dQ-dW

  • Here it is zero.

                                  dU=0,

  • As we know that,

                             dU=C_pdT=0\\\\thus,  dT=0\\\\or , T=constant\\\\i.e, T_1=T_2

  • Thus, the final temperature of the system will be equal to the initial temperature,

                          T_1=T_2=100^0C=373K

<h3>How much work is done?</h3>
  • We found that the process is isothermal,
  • Thus, the work done will be,

                               W=RT*ln(\frac{V_2}{V_1} )=373R*ln(\frac{4}{\frac{4}{3} })\\ \\W=409.8R J

Where, R is the universal gas constant.

<h3>What is a reversible process?</h3>
  • Any process which can be made to proceed in the reverse direction is called reversible process.
  • During which, the system passes through exactly the same states as in the direct process.

Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

Learn more about thermodynamic processes here:

brainly.com/question/28067625

#SPJ1

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