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elixir [45]
3 years ago
8

What is the difference in quark model of a meson and a baryon? ​

Physics
1 answer:
dangina [55]3 years ago
3 0
Mesons are made of a valence quark−antiquark pair (thus have a baryon number of 0), while baryons are made of three quarks (thus have a baryon number of 1).
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(a) Calculate the buoyant force on a 2.00-L helium balloon.
iragen [17]

Answer:

0.0239364 N

0.0057879 N

Explanation:

\rho = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N

The buoyant force is 0.0239364 N

Net vertical force is given by

F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N

The net vertical force is 0.0057879 N

6 0
3 years ago
When an unbalanced force acts on an object,
Gwar [14]
When balanced forces follow up on an object, the object won't move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.
6 0
2 years ago
Read 2 more answers
When two light waves arrive at the same place at the same time they create a?
Montano1993 [528]
Hey there,
<span>They interfere essentially like any other form of wave. 
</span>
Hope this helps :))

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3 0
3 years ago
In the circuit shown, the galvanometer shows zero current. The value of resistance R is :
Tasya [4]

Answer:

its supposed to be (a) 1W

8 0
3 years ago
0. A 3.00-kg block is dropped from rest on a vertical spring whose spring constant is 750 N/m. The block hits the spring, compre
Dmitry_Shevchenko [17]

Answer:

the spring compressed is 0.1878 m

Explanation:

Given data

mass = 3 kg

spring constant k = 750 N/m

vertical distance h = 0.45

to find out

How far is the spring compressed

solution

we will apply here law of mass of conservation

i.e

gravitational potential energy loss = gain of eastic potential energy of spring

so we say m×g×h = 1/2× k × e²

so e² = 2×m×g×h / k

so

we put all value here

e² = 2×m×g×h / k

e² = 2×3×9.81×0.45 / 750

e²  = 0.0353

e = 0.1878 m

so the spring compressed is 0.1878 m

5 0
3 years ago
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