I need the amount of rain in tundra

When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col

jolli1 [7]

Answer:

The nichrome wire is dirty.

The solution is contaminated.

Explanation:

If the nichrome wire is dirty, it may contain sodium contaminants which may be responsible for the yellow flame. The nichrome wire is first inserted into the flame without the sample to check for impurities.

The test solution may also have been contaminated. This leads to the appearance of a colour different from the expected colour of the test cation in the solution.

7 0

4 years ago

Which of the following gases would have the greatest kinetic energy at 300 K?

tekilochka [14]

Answer:

D. All of them would have the same kinetic energy

Explanation:

The expression for the kinetic energy of the gas is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are $N_2,\ NH_3\ and\ Ar$ will posses same value of kinetic energy.</u>

4 0

3 years ago

What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67

zhenek [66]

Answer: 54 atm

Explanation:

I did 67/82.5 then got 0.8121212121. I them divided 44 by 0.81212121 and got 54.1791044776

4 0

3 years ago

A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe

STALIN [3.7K]

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

2.97/294.6 = 3.42/T2

Cross multiply

2.97 × T2 = 294.6 × 3.42

2.97T2 = 1007.532

T2 = 1007.532 ÷ 2.97

T2 = 339.236

The final temperature is 339.2K

5 0

3 years ago

Commercially available aqueous nitric acid has a density of 1.42 g/mL and a concentration of 16 M. Calculate the mass percent of

luda_lava [24]

Answer:

The mass % of HNO3 in the solution is 71.0 %

Explanation:

Step 1: Data given

Density of HNO3 = 1.42 g/mL

Concentration = 16 M = 16 mol /L

Molar mass HNO3 = 63.01 g/mol

Assume the volume = 1L or 1000 mL

Step 2: Calculate mass of the solution

Mass = density * volume

Mass = 1.42 g/mL * 1000 mL

Mass = 1420 grams

Step 3: Calculate moles HNO3

Moles = molarity * volume

Moles = 16 M * 1L

Moles = 16 moles

Step 4: Calculate mass HNO3

Mass HNO3 = moles * molar mass

Mass HNO3 = 16.0 moles * 63.01 g/mol

Mass HNO3 = 1008.16 grams

Step 5: Calculate the mass percent

mass % = (1008.16 grams / 1420 grams) *100%

mass % = 71.0 %

The mass % of HNO3 in the solution is 71.0 %

5 0

3 years ago