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SOVA2 [1]
3 years ago
7

Reactions which do not continue to completion are called _____reactions

Chemistry
2 answers:
SIZIF [17.4K]3 years ago
8 0
I think the answer is reversible. Reversible reaction is a kind of reaction which can react in both direction at the same time. And when the both side reactions get the same speed, the reaction is at a equilibrium state.
Tanzania [10]3 years ago
3 0

Answer:

confirmed!!

Explanation:

ANSWER IS REVERSIBLE!! PLEASE MARK BRAINLIEST

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What attractive force pulls electrons toward protons to form chemical bonds?
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Answer:

C). Electronegativity.

Explanation:

'Electronegativity' is described as the tendency or a measure of the ability of an atom or molecule to attract electrons that leads to the formation of chemical bonds. It is denoted by 'χ', a Greek letter. The elements like Fluorine having a very high rate of electronegativity, its atom would attract the electrons more strongly while the elements with lesser electronegativity like Cesium would possess a lesser tendency to attract electrons towards it in order to form a bond. Thus, <u>option C</u> is the correct answer.

6 0
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At which position in its orbit was the Moon located during the 2015 supermoon total lunar eclipse?
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Under normal conditions, describe how increasing the temperatures effects the solubility of a typical salt
AnnZ [28]
The higher the temperature the higher the solubility
4 0
3 years ago
Help I. have until 11:59 to hand it in ​
Sedbober [7]

This chemical reaction can also be written as

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8 0
3 years ago
G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu
Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains \frac{0.6485}{45}×1000 = 14.411 gm-mole. Thus the solubility product K_{sp}of AgBr = [Ag^{+}]×Br^{-}.

Or, 5.0×10^{-13} = S^{2} (the given value of solubility product of AgBr is 5.0×10^{-13} and the charge of the both ions are same).

Thus S = (5.00×10^{-13})^{1/2} = 7.071×10^{-7} g/mL.

Thus the concentration of Br^{-1} or HBr is 7.071×10^{-7} g/mL.

4 0
4 years ago
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