Answer:
a) MZ₂
b) They have the same concentration
c) 4x10⁻⁴ mol/L
Explanation:
a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.
The salts solubilization reactions and their Kps values are:
MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²
MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³
Thus, the Kps of MZ₂ has a larger value.
b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.
c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:
8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.
Answer: Saturated
A solution that contains the maximum amount of solute that is soluble at a given temperature is said to be saturated.
Explanation:
A Saturated solution is one that contains as much (i.e maximum) solute as it can dissolve at that temperature in the presence of undissolved solute particles.
For instance: if a given volume of water can only dissolve a certain amount of salt in it at room temperature, then, more salt added will not dissolve.
Thus, making the solution saturated.
Answer: The empirical formula of the metal sulfide is 
.
Explanation:
Given: Mass of metal = 20.38 g
Mass of metal sulfide = 31.47 g
Moles is the mass of a substance divided by its molar mass.
So, moles of cobalt (molar mass = 59 g/mol) are as follows.
Moles of bromine (molar mass = 80 g/mol) are as follows.
Now, the ratio of number of moles of cobalt and number of moles of bromine are as follows.
Moles of Co : Moles of Br = 1 : 2
Hence, the empirical formula is .
Thus, we can conclude that the empirical formula of the metal sulfide is .
Answer:
Theoretical yield is 20%.
Explanation:
Percent yield = [(actual yield)/(theoretical yield)]
%
Theoretical yield is calculated amount of product by using stoichiometric ratio between reactant and product.
Actual yield is the amount of product which is experimentally obtained.
Here theoretical yield is 20.0 g and actual yield is 4.0 g.
So, percent yield = 
% = 20%
