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Leto [7]
3 years ago
9

Determine whether the reaction will be spontaneous at high temperatures only, at low temperatures only, at all temperatures, or

no temperatures. (HINT: Use your chemical sense and your real-world knowledge to predict the signs of delta Hrxn & delta Srxn)
4Fe(s) + 3O2(g) ----> 2Fe2O3(s) [rust]


Circle one:High T, Low T, All T, No T
Chemistry
1 answer:
LiRa [457]3 years ago
5 0

Answer:

The rusting of iron is spontaneous at low temperatures.

Explanation:

The given chemical reaction is:

4Fe(s) + 3O2(g) ----> 2Fe2O3(s) [rust]

The rusting of iron is a chemical reaction in which iron reacts with oxygen in presence of moisture and forms iron oxide.

This reaction takes place in a faster rate when there is low temperatures in the atmosphere.

When temperature is low, the moisture in the atmosphere is more and hence, rate of rusting is more.

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Help?
tino4ka555 [31]

Answer:

There is 52.33 grams of water produced.

Explanation:

Step 1: Data given

Mass of propane burned = 32.00 grams

Molar mass of propane = 44.1 g/mol

Oxygen is in excess

Molar mass of water = 18.02 g/mol

Step 2: The balanced equation

C3H8 + 5O2 → 4H2O + 3CO2

Step 3: Calculate moles of propane

Moles of propane = mass propane / molar mass of propane

Moles of propane = 32.00 grams / 44.1 g/mol

Moles of propane = 0.726 moles

Step 4: Calculate moles of H2O

Propane is the limiting reactant.

For 1 mol of propane consumed, we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2

For 0.726 moles of propane we'll have 4*0.726 = 2.904 moles of H2O

Step 5: Calculate mass of H2O

Mass of H2O = moles of H2O * molar mass of H2O

Mass of H2O = 2.904 moles * 18.02 g/mol

Mass of H2O = 52.33 grams

There is 52.33 grams of water produced.

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