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iren [92.7K]
3 years ago
15

In a typical ecosystem, the largest amount of biomass should be found at which level?

Chemistry
1 answer:
Ugo [173]3 years ago
4 0

Answer: producers

Explanation:

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Define an ion in chemistry
REY [17]
Ion is an atom or molecule with a net electric charge due to loss or gain of one or more electrons.
4 0
3 years ago
What relationship does Avogadro's law describe?
LenaWriter [7]

Answer:

D. The relationship between volume and moles

Explanation:

Amedo Avogadro found the relationship between the volume of a gas and the number of molecules contained in the volume.

The law states that "equal volume of all gases at the same temperature and pressure contains the same number of molecules or moles".

Mathematically:

                         V ∝ n (P,T constant)

4 0
3 years ago
A very loud sound has a high _____.
DENIUS [597]

Answer:

Resting Point

Explanation:

4 0
2 years ago
Read 2 more answers
There is a 30g of be-11 it has a half-life of about 14 seconds how much will be left in 28 seconds
Lelu [443]

There will be 7.5 g of Be-11 remaining after 28 s.

If 14 s = 1 half-life, 28 s = 2 half-lives.

After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.

After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.

In symbols,

<em>N</em> = <em>N</em>₀(½)^<em>n</em>

where

<em>n</em> = the number of half-lives

<em>N</em>₀ = the original amount

<em>N</em> = the amount remaining after <em>n</em> half-lives

6 0
3 years ago
The mineral enargite is 48.41% cu, 19.02% as, and 32.57% s by mass. what is the empirical formula of enargite?
LuckyWell [14K]
Empirical formula is the simplest ratio of whole numbers of components in a compound. 
Assuming for 100 g of the compound 
                                Cu                                 As                             S
mass                      48.41 g                          19.02 g                      32.57 g
number of moles    48.41 / 63.5 g/mol      19.02 / 75 g/mol        32.57 / 32 g/mol 
                                = 0.762 mol                = 0.2536 mol            = 1.018 mol 
divide by the least number of moles 
                               0.762 / 0.2536             0.2536 / 0.2536         1.018 / 0.2536
                               = 3.00                          = 1.00                         = 4.01
once they are rounded off 
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
8 0
3 years ago
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