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BARSIC [14]
3 years ago
8

What is the volume of 0.04 mol of a gas at 0.9 kPa and 20°C?

Chemistry
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

The correct answer is option A.

Explanation:

Pressure of the gas ,P=  0.9 kPa = 0.008882 atm

1 kPa = 0.0098 atm

Number of moles gases = n  = 0.04 mol

Temperature of the gas ,T =20°C = 293 K

Volume of the gas = V

Using An Ideal gas equation:

PV=nRT

V=\frac{nRT}{P}=\frac{0.04 mol\times 0.0820 atm L/mol K\times 293 K}{0.008882 atm}=108.20 L\approx 108 L

Hence, the correct answer is option A.

Annette [7]3 years ago
7 0
A. 108 L is the winner!
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anuvia, the trade name for sitagliptin, was introduced in 2006 for the treatment of type 2 diabetes. In what type of orbital doe
Aleonysh [2.5K]

Answer: hello your question is poorly written below is the complete question

answer:

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 :  sp³  orbital

For N2:  p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

5 0
2 years ago
What is a process of reacting an acid with a base until an equivalence point is reached
Brrunno [24]
TITRATION is the process of reaching equilibrium between acids and bases.
8 0
3 years ago
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
The indicator methyl red has different molecular structures at high and low pH.
Novosadov [1.4K]

Answer:

a. True

Explanation:

Methyl red is an indicator widely used in quality control of oxides as Zinc oxide in the titration with sulfuric acid.

As is used in titrations of acid-base reactions the indicator change in colour. Is red when the pH < 4.4 (Acidic Solutions) and is yellow when pH > 6.2 (Neutral-Basic solutions).

A change in colour means the structure of the indicator is changing with pH. Thus, the answer is:

<h3>a. True </h3>

6 0
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Can matter be created or<br> destroyed?<br><br> Yes or No
anzhelika [568]

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No

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5 0
2 years ago
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