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4 years ago

What is the volume of 0.04 mol of a gas at 0.9 kPa and 20°C?

Chemistry

2 answers:

Firdavs [7]4 years ago

8 0

Answer:

The correct answer is option A.

Explanation:

Pressure of the gas ,P= 0.9 kPa = 0.008882 atm

1 kPa = 0.0098 atm

Number of moles gases = n = 0.04 mol

Temperature of the gas ,T =20°C = 293 K

Volume of the gas = V

Using An Ideal gas equation:

PV=nRT

$V=\frac{nRT}{P}=\frac{0.04 mol\times 0.0820 atm L/mol K\times 293 K}{0.008882 atm}=108.20 L\approx 108 L$

Hence, the correct answer is option A.

Annette [7]4 years ago

7 0

A. 108 L is the winner!

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3 years ago

How do i find a ionic formula? <br><br>for example Ca2+ & S2-

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Example #1 write the chemical formula for Calcium Oxide

Step 1

-Find the Atomic symbol of the metal and non-metal on the periodic table

CaO

Step 2

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which are Ca 2+ and O 2-

Step 3

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They are already balanced out

Here´s the chemical formula for Calcium Oxide

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Example 2 write the chemical formula for Aluminum Oxide

Step 1

-Find the Atomic symbol of the metal and non-metal on the periodic table

Step 2

Find the charges for Aluminum and Oxygen

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3 years ago

How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?

natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

N₂: 1 mole
H₂: 3 moles
NH₃: 2 moles

The molar mass of the compounds is:

N₂: 14 g/mole
H₂: 2 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

N₂: 1 mole ×14 g/mole= 14 grams
H₂: 3 moles ×2 g/mole= 6 grams
NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

$moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}$