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BARSIC [14]
3 years ago
8

What is the volume of 0.04 mol of a gas at 0.9 kPa and 20°C?

Chemistry
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

The correct answer is option A.

Explanation:

Pressure of the gas ,P=  0.9 kPa = 0.008882 atm

1 kPa = 0.0098 atm

Number of moles gases = n  = 0.04 mol

Temperature of the gas ,T =20°C = 293 K

Volume of the gas = V

Using An Ideal gas equation:

PV=nRT

V=\frac{nRT}{P}=\frac{0.04 mol\times 0.0820 atm L/mol K\times 293 K}{0.008882 atm}=108.20 L\approx 108 L

Hence, the correct answer is option A.

Annette [7]3 years ago
7 0
A. 108 L is the winner!
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Which sample contains more atoms:<br> 3.89 g of nickel or 6.61 g of silver?<br> Defend your answer.
Alenkinab [10]
Nickel contains more atoms
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2 years ago
I NEED HELP ASAP IF YOU GET IT CORRECT I WILL MARK YOU AS BRAINLIEST
masya89 [10]

Answer:

2 tall 2 short.

Explanation:

If 1 is tall, and 1 is short, 50% would be tall, and the other 50% would be short.

4 0
3 years ago
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Calcium chloride reacts with sodium hydroxide to form solid calcium hydroxide, Ca(OH)2. The balanced net ionic equation is
katen-ka-za [31]

Answer:

Ca²⁺ + 2 OH⁻ → Ca(OH)₂(s)

Explanation:

In chemistry, the net ionic equation is a way to write a chemical reaction whereas you write only the ions that are involved in the reaction.

When calcium chloride, CaCl₂ reacts with sodium hydroxide, NaOH to produce Ca(OH)₂ the only ions involved in the reaction are Ca²⁺ and OH⁻, thus, the balanced net ionic equation is:

<em>Ca²⁺ + 2 OH⁻ → Ca(OH)₂(s)</em>

<em>Cl⁻ and Na⁺ are not involved in the reaction and you don't have to write them.</em>

5 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
what is the best course of action if solid material remains in the flask after the heating step of recrystallization
lys-0071 [83]

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

7 0
3 years ago
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