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tangare [24]
4 years ago
14

PLEASE HELP ASAP 15 BRAINLY POINTS

Mathematics
2 answers:
rewona [7]4 years ago
8 0

1) b

2) no

3) c

4) a

emmainna [20.7K]4 years ago
6 0

1.) The answer is (B) No, because direct variation is written as y = kx, but the problem was not written that way.

2.) Answer: Yes; if you write x = ky, you will find that each x value given multiplied by a common k equals a corresponding y value.

3.) Answer: No; each x value does not multiply by a constant k to get the y values.

4.) Answer: Yes; each x value multiplies by 2.2 to get each corresponding y value.

5.) Answer: B; this is the only one that isn't or can't be written in y = kx form.

6.) Answer: Yes & -3; y + 3x = 0 can be written as y = -3x, which is a direct variation equation. The constant is just the -3.

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MakcuM [25]
While since Rajeev is already below the surface by 12.6 ft it’ll be negative (-12.6) and since he went down another 8.7 ft it’ll just be minus since he is still going under, so -12.6-8.7 will be your answer. :)
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3 years ago
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How many solutions are there to the equation below? 17 x - 8 = 3x + 16<br>maqth ​
vazorg [7]

Answer:

There is one solution and that answer is mixed number form  1 5/7 or exact form 12/7

Step-by-step explanation:

8 0
3 years ago
Which expressions are equivalent to 4(x+1) + 7(x+3)? Select two answers.
Natalija [7]

Answer:

9(x+3) + 2(x+3) or 10(x+2) +(x+5)

Step-by-step explanation:

First you want to distribute the equation.

4(x+1) + 7(x+3) multiplied out is

4x + 4 + 7x + 21

Now we add like terms so it comes out to

11x + 25

Two expressions that can come out to equal 11x + 25 is. 9(x+3) + 2(x+3) or 10(x+2) +(x+5)

7 0
3 years ago
A student got 68% of the questions correct on the Social Studies test. If there were 50 questions, how many questions did they g
kaheart [24]

Answer:

The answer is 34.

8 0
3 years ago
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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