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juin [17]
3 years ago
15

Under the right conditions aluminum will react with chlorine to produce aluminum chloride.

Chemistry
1 answer:
salantis [7]3 years ago
8 0

Answer:

m_{Al}=9.42gAl

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2}  *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl

Regards!

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Classify the following alcohol as primary,
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<h3>What are alcohols?</h3>

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Now we know that the alcohols are those organic compounds that contains the -OH group. The could be aliphatic or alicyclic compounds. We shall now proceed to name the kind of alcohols that each of the compounds shown are;

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2 years ago
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M_1V_1=M_2V_2

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M_2\text{ and }V_2 are the molarity and volume of NaOH.

We are given:

M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL

Putting values in above equation, we get:

6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL

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4 0
4 years ago
A foil boat measures 4.0cm by 5.0cm and has a mass of 100.0g. If you put the boat in water, how far will it sink? (Recall the de
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Answer:

Let the volume of the block of wood be

V

c

m

3

and its density be

d

w

g

c

m

−

3

So the weight of the block

=

V

d

w

g

dyne, where g is the acceleration due to gravity

=

980

c

m

s

−

2

The block floats in liquid of density

0.8

g

c

m

−

3

with

1

4

t

h

of its volume submerged.So the upward buoyant force acting on the block is the weight of displaced liquid

=

1

4

V

×

0.8

×

g

dyne.

Hence by cindition of floatation

V

×

d

w

×

g

=

1

4

×

V

×

0.8

×

g

⇒

d

w

=

0.2

g

c

m

-3

,

Now let the density of oil be

d

o

g

c

m

-3

The block floats in oil with 60% of its volume submerged.So the buoyant force balancing the weight of the block is the weight of displaced oil =

60

%

×

V

×

d

o

×

g

dyne

Now applying the condition of floatation we get

60

%

×

V

×

d

o

×

g

=

V

×

d

w

×

g

⇒

60

100

×

V

×

d

o

×

g

=

V

×

0.2

×

g

⇒

d

o

=

0.2

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6

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3

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