Simple cellll importable
Ikr
Answer:
Explanation:
Answer:
Approximately
upwards (assuming that
.)
Explanation:
External forces on this astronaut:
- Weight (gravitational attraction) from the earth (downwards,) and
- Normal force from the floor (upwards.)
Let
denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:
.
Let
denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be
.
Let
denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be
.
Rearrange
to obtain an expression for the magnitude of the normal force on this astronaut:
.
Answer:
distance = 6 m
Explanation:
- Distance is a scalar quantity (so, only magnitude, no direction), and it is calculated as the scalar sum of all the distances travelled by an object during its motion, regardless of the direction. So, in this problem, the distance covered by the pinecone is
d = 4 m + 2 m = 6 m
- Displacement is a vector quantity (magnitude+direction), and its magnitude is calculate as the distance in a straight line between the final position and the initial position of the object. In this case, the final position is 2 m west and the initial position is 0 m, so the displacement of the pinecone is
d = 2 m west - 0 m = 2 m west
So, a scalar quantity from this scenario is
distance = 6 m